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IceJOKER [234]
3 years ago
5

2/5 as a decimal and percent

Mathematics
1 answer:
lukranit [14]3 years ago
7 0
Decimal: .4
Percent: 40%
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Find the area of the circle<br> Pls help quick
tigry1 [53]

Answer:

153.86.

Step-by-step explanation:

Formula for area of a circle: A= Pi R (R is radius) squared. First fill in the numbers: 3.14x7^2 Then Solve for the squared: 7^2=49, then finally multiply 49x3.14 which gets you to 153.86.

7 0
3 years ago
Suppose that there are two types of tickets to a show:Advance and same-day. Advance tickets cost $35 and same day tickets cost $
sdas [7]

Answer:    30 $15 tickets and 20 $35 tickets

Step-by-step explanation:

.X%2BY=50

2.15X%2B35Y=1150

From eq. 1,

15X%2B15Y=750

Subtract from eq. 2,

15X%2B35Y-15X-15Y=1150-750

20Y=400

Y=20

Then,

X%2B20=50

X=30

30 $15 tickets and 20 $35 ticket

Hope it helps

5 0
3 years ago
The table shows the solution to the equation |2x − 3| − 1 = 2: Step 1 |2x − 3| = 2 + 1 Step 2 |2x − 3| = 3 Step 3 2x − 3 = 3 or
Ronch [10]
Step 1 is the correct answer because to begin solving you must add 1 to both sides of the equation
4 0
3 years ago
I can write numerical expressions involving whole-number exponents
DerKrebs [107]

Answer:

yes

Step-by-step explanation:

nothing much u have to do like what ur teacher said

7 0
3 years ago
a card player selects a playing card from a well-shuffled deck of standard playing cards and sees if the card is a red card or n
DIA [1.3K]

It is not binomial random variable , since the number of red cards is unknown in the deck of cards in the starting of experiment.

As given in the question,

Number of cards are unknown.

Number of red cards are unknown in the starting of experiment.

Number of times process done =10

For binomial random variable number of red cards should be known.

Therefore, it is not binomial random variable , since the number of red cards is unknown in the deck of cards in the starting of experiment.

Learn more about binomial random variable here

brainly.com/question/14282621

#SPJ4

8 0
1 year ago
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