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3 years ago

What is this plot/table/graph? And how do I read it?

Mathematics

2 answers:

jeka943 years ago

8 0

Step-by-step explanation:

A we measure across the x-axis. First so it is two and then we measure on the y-axis. Up three so

telo118 [61]3 years ago

5 0

It is a plot i know because my math teacher taught me this yesterday.

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HELPP!! I report wrong answers!!

Zarrin [17]

A : 12+1.5x=26 :))))

7 0

3 years ago

Can someone help me in this plssss I really need it

kompoz [17]

Answer:

$\boxed{-3xy^{2}\sqrt [3] {2x^{2}}}$

Step-by-step explanation:

Your expression is

$\sqrt [3] {-54x^{5}y^{6}}$

Here's how I would simplify it.

$\begin{array}{rcll}\sqrt [3] {-54x^{5}y^{6}} & = & \sqrt [3] {(-1)^{3}\times 2 \times 27 \times x^{2} \times x^{3} \times y^{6}} & \text{Factored the cubes}\\& = & \sqrt [3] {(-1)^{3} \times 3^{3}\times x^{3} \times y^{6}\times 2 \times x^{2}} & \text{Grouped the cubes}\\\end{array}$

$\begin{array}{rcll}& = & \sqrt [3] {(-1)^{3} \times {3^{3}\times x^{3} \times y^{6}}} \times\sqrt [3] { 2 \times x^{2}} & \text{Separated the cubes}\\&=& \mathbf{-3xy^{2}\sqrt [3] {2x^{2}}} & \text{Took cube roots}\\\end{array}$

$\text{The simplified expression is $\boxed{\mathbf{-3xy^{2}\sqrt [3] {2x^{2}}}}$}$

6 0

4 years ago

Please answer right away and don’t guess

DochEvi [55]

Answer: Third Option

$P (M\ or\ N) = 0.8$

Step-by-step explanation:

In this case, we have two non-disjoint events.

So the probability of M or N occurring is

$P (M\ or\ N) = P(M) + P(N) - P (M\ and\ N)$

We know that in this problem

$P(M) = 0.7\\\\P(N) = 0.5$

$P(M\ and\ N) = 0.4$

$P (M\ or\ N) = 0.7 + 0.5 - 0.4$

$P (M\ or\ N) = 0.8$

The answer is the third option

6 0

3 years ago

Based on the table, which best predicts the end behavior

kotykmax [81]

Answer:

Third option.

Step-by-step explanation:

In the picture attached, the question is shown. There we can see that as x gets bigger (x → ∞), f(x) gets smaller (f(x) → -∞ ). On the other hand, as x gets smaller (x → -∞), f(x) gets bigger (f(x) → ∞ ).

4 0

3 years ago

What is the absolute extrema of the function on the closed interval<br> f (x)=x^2+2x-4, [-1,1]

Misha Larkins [42]

$f(x)=x^2+2x-4\\
f'(x)=2x+2\\\\
2x+2=0\\
2x=-2\
x=-1\\\\
f(-1)=(-1)^2+2\cdot(-1)-4=1-2-4=-5\\
f(1)=1^2+2\cdot1-4=1+2-4=-1\\\\
f_{min}=-5\\
f_{max}=-1$

5 0

3 years ago