To determine the probability that one or the other circumstances will occur, you will count the number of possible outcomes and divide it by all the possible outcomes.
#of female teaching assistants + # of male teaching assistants + # of female professors
6 + 16 + 11 = 33
Total = 41
33/41 = 80
There is a approximate 80% probability that one or the other will occur.
Answer:
3rd graph down
Step-by-step explanation:
greens are x and carrots are y in my equations
2x - y >= 3
x + 2y < 4
The first equation is solid and will highlight everything to the right of it because it is a >
the second is dashed and will highlight everything to the left of it because it is a <
the only 2 graphs that show this are 1 and 3
looking at the points you can see that the points for the solid line are both the same so ignore those and go to the dashed lined ones.
on the first graph the points are (0,4)
plugging those into our equation gives us 0 + 2*4 <4
or 8<4 which doesnt make sense making 3 the correct graph
(sorry my answer wasnt posting so i had to start over and make it less detailed, but comment if you need any explanation)
Answer:
37.7125
Step-by-step explanation:
35 * 1.0775
Answer:
-2
Step-by-step explanation:
The equation of the line is written in y=mx+c form, where m is the gradient and c is the y-intercept.
In this case, your m is a -2 and your c is a -3.
Hence the gradient of the line is -2.
Answer:
E
Step-by-step explanation:
Solution:-
- We are to investigate the confidence interval of 95% for the population mean of walking times from Fretwell Building to the college of education building.
- The survey team took a sample of size n = 24 students and obtained the following results:
Sample mean ( x^ ) = 12.3 mins
Sample standard deviation ( s ) = 3.2 mins
- The sample taken was random and independent. We can assume normality of the sample.
- First we compute the critical value for the statistics.
- The z-distribution is a function of two inputs as follows:
- Significance Level ( α / 2 ) = ( 1 - CI ) / 2 = 0.05/2 = 0.025
Compute: z-critical = z_0.025 = +/- 1.96
- The confidence interval for the population mean ( u ) of walking times is given below:
[ x^ - z-critical*s / √n , x^ + z-critical*s / √n ]
Answer: [ 12.3 - 1.96*3.2 / √24 , 12.3 + 1.96*3.2 / √24 ]