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3 years ago

What is the value of x in the figure below

Mathematics

1 answer:

enot [183]3 years ago

6 0

Answer:

X=110°

Step-by-step explanation:

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Directions on a box of 5 cups of wallpaper paste are to mix the contents with 4 qt of water. To mix a smaller batch using 1 cup

PtichkaEL [24]

Step-by-step explanation:

For standard embossed we recommend 8 pints/4.5L for 4-5 rolls. For heavy embossed we recommend 7 pints/4L for 3-4 rolls.

hope that help you

4 0

2 years ago

How do I solve for x

Alchen [17]

Greetings!

To find the length of any side of a right triangle, you can use the Pythagorean Thereom. It states that the squares of two sides are equal to the square of the hypotenuse:
$a^2+b^2=c^2$

Input the information from the diagram into the formula:
$(x)^2+(x+7)^2=(13)^2$

Expand each term:
$(x)^2+(x+7)^2=(13)^2$

$x^2+((x+7)(x+7))=169$

$x^2+(x(x+7)+7(x+7))=169$

$x^2+x^2+7x+7x+49=169$

Combine like terms:
$2x^2+14x+49=169$

Add -169 to both sides:
$(2x^2+14x+49)+(-169)=(169)+(-169)$

$2x^2+14x-120=0$

Factor out the Common Term (2):
$2(x^2+7x-60)=0$

Factor the Complex Trinomial:
$2(x^2-5x+12x-60)=0$

$2(x(x-5)+12(x-5))=0$

$2(x-5)(x+12)=0$

Set Factors to equal 0:
$x-5=0$

$x=5$

or

$x+12=0$

$x=-12$

However, since we are solving for the side length, the only possible answer is 5 (a shape can't have a side with a negative length.)

The Solution Is:
$\boxed{x=5}$

I hope this helped!
-Benjamin

6 0

3 years ago

Mai has 25 yards of ribbons. She cut them into 1/4 yard pieces. How many pieces can she get? How many pieces can she get? Which

natima [27]

Use Division it will help you

5 0

3 years ago

if rhombus ABCD were reflected across the x axis to create rhombus A'B'C'D', what would the measure of angle D' be?

Mrac [35]

Answer:

D.64

Step-by-step explanation:

A linear line equals up to 180

A+D=180

Substitute 116 for A

116+D=180

Subtract 116 from both sides

D=64

A reflection across the x-axis won't change the measure of an angle

The answer is 64.

8 0

3 years ago

Find the sum of the numbers divisible by 7 between 30 and 500

brilliants [131]

Answer:

17822

Step-by-step explanation:

The number that are divisible by 7 between 30 and 500 are as follows :

35, 42,49,.....,497

It will form an AP with first term, a = 35 and common difference, d = 7

Let there are n terms in the AP.

nth term of an AP is given by :

$a_n=a+(n-1)d$

Putting all the values,

$497=35+(n-1)7\\\\462=(n-1)7\\\\n-1=66\\\\n=67$

Now, the sum of n terms of an AP is given by :

$S_n=\dfrac{n}{2}[2a+(n-1)d]$

Putting all the values,

$S_n=\dfrac{67}{2}[2(35)+(67-1)7]\\\\S_n=17822$

Hence, the sum of the numbers that are divisible by 7 between 30 and 500 is 17822.

6 0

3 years ago