Answer:
$36,400
Step-by-step explanation:
Mr Jamison deposited $100 in January
February=3*100=$300
March=3{3(100)=3^2(100)=9*100=$900
April=3^3(100)=27*100=$2,700
May=3^4(100)=81*100=$8,100
June=3^5(100)=243*100=$24,300
Total amount=$100 + $300 + $900 + $2700 + $8100 + $24300
=$36,400
The total amount deposited by Mr Jamison on June 15 is $36,400
