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3 years ago

Type the correct answer in the box. Use numerals instead of words.

Mathematics

1 answer:

Ksivusya [100]3 years ago

4 0

Answer:

$36,400

Step-by-step explanation:

Mr Jamison deposited $100 in January

February=3*100=$300

March=3{3(100)=3^2(100)=9*100=$900

April=3^3(100)=27*100=$2,700

May=3^4(100)=81*100=$8,100

June=3^5(100)=243*100=$24,300

Total amount=$100 + $300 + $900 + $2700 + $8100 + $24300

=$36,400

The total amount deposited by Mr Jamison on June 15 is $36,400

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3 years ago

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Let "x" represent the weight of the toppings. We know that we can have any number of toppings. This means that one may ask for no toppings at all too.

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Answer:

Then the probability distribution is:

P(0) = 1/3

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Step-by-step explanation:

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P(0) = 2/6 = 1/3

The probability of drawing one green marble (X = 1)

is:

First, you draw a green marble with a probability of 4/6

Then you draw the red one, but now there are 5 marbles in the jar (2 red ones and 3 green ones), then the probability is 2/5

The joint probability is:

P(1) = (4/6)*(2/5) = (2/3)*(2/5) = 4/15

The probability of drawing two green marbles (X = 2)

Again, first we draw a green marble with a probability of 4/6

Now we draw again a green marble, now there are 3 green marbles and 5 total marbles in the jar, so this time the probability is 3/5

Now we draw the red marble (there are 2 red marbles and 4 total marbles in the jar), with a probability of 2/4

The joint probability is:

P(2) = (4/6)*(3/5)*(2/4) = (2/6)*(3/5) = 1/5

The probability of drawing 3 green marbles (X = 3)

At this point you may already understand the pattern:

First, we draw a green marble with a probability 4/6

second, we draw a green marble with a probability 3/5

third, we draw a green marble with a probability 2/4

finally, we draw a red marble with a probability 2/3

The joint probability is:

P(3) = (4/6)*(3/5)*(2/4)*(2/3) = (2/6)*(3/5)*(2/3) = (1/5)*(2/3) = (2/15)

Finally, the probability of drawing four green marbles (X = 4) is given by:

First, we draw a green marble with a probability 4/6

second, we draw a green marble with a probability 3/5

third, we draw a green marble with a probability 2/4

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Then the probability distribution is:

P(0) = 1/3

P(1) = 4/15

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P(3) = 2/15

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The expected value will be:

EV = 0*P(0) + 1*P(1) + 2*P(2) + 3*P(3) + 4*P(4)

EV = 1*(4/15) + 2*( 1/5) + 3*( 2/15) + 4*(1/15 ) = 1.33

So we can expect to draw 1.33 green marbles in this experiment.

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