Answer:
There is also an attachment below
Explanation:
Since we are talking about binary search, let's assume that the items are sorted according to some criteria.
Time complexity of binary search is O(logN) in worst case, best case and average case as well. That means it can search for an item in Log N time where N is size of the input. Here problem talks about the item not getting found. So, this is a worst case scenario. Even in this case, binary search runs in O(logN) time.
N = 700000000.
So, number of comparisions can be log(N) = 29.3 = 29.
So, in the worst case it does comparisions 29 times
Operating systems are the software that supports the basic functioning of the computer. Windows Virtual Desktop is an Azure compute service that will help solve the problem.
<h3>What is Windows Virtual Desktop?</h3>
Windows Virtual Desktop is an app virtualization service of Azure that operates on the cloud platform. It includes standard operating procedures that can be used by users with multiple OS.
Azure's Virtual Desktop supports different versions of window OS. This type of system is majorly used in remote work demands and specialized workloads.
Therefore, Windows Virtual Desktop is an Azure compute service.
Learn more about Azures service here:
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The correct answer is B. Palpation
Explanation:
In a medical exam or similar, the palpation involves touching different parts of the body to feel the organs and structures in this. This process is essential in diagnosis because palpation can reveal inflammation, pain in certain areas, or abnormalities. Additionally, palpation requires a broad knowledge of anatomy that allows health professionals to understand the structures of the body when they touch these and how to determine abnormalities. Thus, the part of an examination in which body parts are touched and felt is palpation.
Answer:
Answer explained
Explanation:
From the previous question we know that while searching for n^(1/r) we don't have to look for guesses less than 0 and greater than n. Because for less than 0 it will be an imaginary number and for rth root of a non negative number can never be greater than itself. Hence lowEnough = 0 and tooHigh = n.
we need to find 5th root of 47226. The computation of root is costlier than computing power of a number. Therefore, we will look for a number whose 5th power is 47226. lowEnough = 0 and tooHigh = 47226 + 1. Question that should be asked on each step would be "Is 5th power of number < 47227?" we will stop when we find a number whose 5th power is 47226.