To solve the question we shall use the formula for the range given by:
Horizontal range, R=[v²sin 2θ]/g
plugging in our values we get:
500=[160²×sin 2θ]/10
5000=160²×sin 2θ
0.1953=sin 2θ
thus:
arcsin 0.1953=2θ
11.263=2θ
hence:
θ=5.6315°~5.63
JK where T is the midpoint. J >>>>> T >>>>> K.
JK = 5x - 3
JT = 2x + 1
Because T is the midpoint, it means that JT = TK
So, JT + TK = JK
(2x + 1) + (2x + 1) = 5x - 3
4x + 2 = 5x - 3
4x - 5x = -3 - 2
-x = -5
x = 5
JK = 5x - 3
JK = 5(5) - 3
JK = 25 -3
JK = 22
The length of JK is 22.
Answer: 
or 
Step-by-step explanation:
We need to divide 300 by 20.
We get or .
