To find the area of a rhombus, the formula is d1(d2)/2
d1 is 4+4 or 8
d2 is 7+10 or 17
17(8)=136
136/2=68
Answer:
Part c
Step-by-step explanation:
In quadratic equations of real coefficients, the complex roots always occur in conjugate bases. It means, if, 2 + 3i is one of the roots and then the second root must be 2 - 3i.
Answer:
246.3%
the complete question is found in the attached document
Step-by-step explanation:
1st step:
using 1936 data,
w1= 356% = 3.56(356/100) , H= 79 feet
specific gravity = 2.65
Sₓ= 100%= 1
initial void ratio(e₀)= (w1 x specific gravity)/Sₓ
=3.56 x 2.65/1 = 9.434
2nd step
using 1996 data
ΔH= 22ft
ΔH/H = Δe/(1 + e₀)
22/79 = Δe/(1+9.434)
0.278=Δe/10.434
Δe= 0.278 x 10.434
Δe= 2.905
Δe= e₀ - eₓ
eₓ= e₀-Δe
eₓ= 9.434 - 2.905
eₓ= 6.529
3rd step
calculating water content in 1996
eₓ =6.529, specific gravity= 2.65, Sₓ= 100%
W2 X 2.65 = 1 x 6.529
w2 = 6.529/2.65 = 2.463 = 246.3%
Step-by-step explanation:
y |X(the sign for protionality) 1/√x
y = 7 when x = 36
y = k/√x
7 = k/√36
7 = k / 6 cross multiply
k = 7×6
k = 42
find y when x is 4
y = 42/√x
y = 42/√4
y = 42/2
y = 21