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3 years ago

Insert grouping symbols to make each number sentence true 7*8-6+3=17

Mathematics

1 answer:

NNADVOKAT [17]3 years ago

7 0

Answer:

7*(8-6)+3

Step-by-step explanation:

Grouping symbols are parentheses; trial and error can lead you to this answer.

Checking, we must use order of operations (PEMDAS). First, we evaluate what's inside parentheses.

7 * 2 + 3

Then multiply:

14 + 3

Then add

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Use the frequency table to determine how many students received a score of 80 or better on an English exam.

Sveta_85 [38]

10 students scored above an 80

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3 years ago

For f(x) = 3x - 1 and g(x) = x+2, find (f – g)(x).

kobusy [5.1K]

Well, I bet you want your answer right away! So here it is.

Given f (x) = 3x + 2 and g(x) = 4 – 5x, find (f + g)(x), (f – g)(x), (f × g)(x), and (f / g)(x).

To find the answers, all I have to do is apply the operations (plus, minus, times, and divide) that they tell me to, in the order that they tell me to.

(f + g)(x) = f (x) + g(x)

= [3x + 2] + [4 – 5x]

= 3x + 2 + 4 – 5x

= 3x – 5x + 2 + 4

= –2x + 6

(f – g)(x) = f (x) – g(x)

= [3x + 2] – [4 – 5x]

= 3x + 2 – 4 + 5x

= 3x + 5x + 2 – 4

= 8x – 2

(f × g)(x) = [f (x)][g(x)]

= (3x + 2)(4 – 5x)

= 12x + 8 – 15x2 – 10x

= –15x2 + 2x + 8

\left(\small{\dfrac{f}{g}}\right)(x) = \small{\dfrac{f(x)}{g(x)}}(gf)(x)=g(x)f(x)= \small{\dfrac{3x+2}{4-5x}}=4−5x3x+2

My answer is the neat listing of each of my results, clearly labelled as to which is which.

( f + g ) (x) = –2x + 6

( f – g ) (x) = 8x – 2

( f × g ) (x) = –15x2 + 2x + 8

\mathbf{\color{purple}{ \left(\small{\dfrac{\mathit{f}}{\mathit{g}}}\right)(\mathit{x}) = \small{\dfrac{3\mathit{x} + 2}{4 - 5\mathit{x}}} }}(gf)(x)=4−5x3x+2

Hope I helped! :) If I did not help that's okay.

-Duolingo

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3 years ago

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abruzzese [7]

6-7n=29 would be your answer

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<img src="https://tex.z-dn.net/?f=%5Csqrt%7B%5C%5C%5Cfrac%7B9%2B%5Csqrt%7B17%7D%20%7D%7B2%7D" id="TexFormula1" title="\sqrt{\\\f

Alborosie

$\huge\underline\pink{✏ANSWER}$

<h2>Hello and sorry but it's a Gatheted Question Can you fix it Can you? </h2>

Sorry for answering a nonsense

#BrainliestBunch

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