x=25,y=15 Not to sure abt this answer but I think I got it
Answer:
Height = 14.4
Step-by-step explanation:
The diagonals meet at right angles. Interesting property.
The hypotenuse is the side of the rhombus = 15 cm
One of the sides of the small triangles created by the intersection of the diagonals = 24/2 = 12
You can find the other side of the the triangle by using the Pythagorean Theorem
a^2 + b^2 = c^2
c = 15
a = 12
b = ?
12^2 + b^2 = 15^2
144 + b^2 = 225
b^2 = 225 - 144
b^2 = 81
b = 9
The area of this right angle = 9 * 12/2 = 54
There are 4 of them so 4 * 54 = 216
That's the area of the rhombus.
The h= Area / b
b = 15
h = 216/15
h = 14.4
The answer to, Is the Triangle with side lengths of 10 in., 24 in., and 26 in, a right triangle is: Yes. For right triangles, the sum of the squares of the shorter sides is equal to the square of the longer side. Thus, this is a right triangle if 10^2+24^2=26^2. Expanding these squares, we have 100+576=676, which is true. Thus, the triangle is right.
Answer:
(-2, 6)
General Formulas and Concepts:
<u>Pre-Algebra</u>
- Order of Operations: BPEMDAS
- Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
- Solving systems of equations by graphing
Step-by-step explanation:
<u>Step 1: Define systems</u>
4x - 2y = -20
7x + 2y = -2
<u>Step 2: Rewrite systems</u>
4x - 2y = -20
- Add 2y to both sides: 4x = 2y - 20
- Divide 4 on both sides: x = 1/2y - 5
<u>Step 3: Redefine systems</u>
x = 1/2y - 5
7x + 2y = -2
<u>Step 4: Solve for </u><em><u>y</u></em>
<em>Substitution</em>
- Substitute in <em>x</em>: 7(1/2y - 5) + 2y = =-2
- Distribute 7: 7/2y - 35 + 2y = -2
- Combine like terms: 11/2y - 35 = -2
- Add 35 to both sides: 11/2y = 33
- Isolate <em>y</em>: y = 6
<u>Step 5: Solve for </u><em><u>x</u></em>
- Define original equation: 7x + 2y = -2
- Substitute in <em>y</em>: 7x + 2(6) = -2
- Multiply: 7x + 12 = -2
- Subtract 12 on both sides: 7x = -14
- Divide 7 on both sides: x = -2
<u>Step 6: Graph systems</u>
<em>Check the system.</em>