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4 years ago

Which are the possible size lengths of a triangle?

Mathematics

2 answers:

IgorC [24]4 years ago

5 0

Answer:

All of those which summed are more that the third side, so the second is the only possible answer.

Step-by-step explanation:

4+8 = 12 which is greather than 10

mafiozo [28]4 years ago

4 0

Answer:

Step-by-step explanation:

you need to be able to add all the numbers up and divide by three. D is the only one that makes sense because 8+10=18 18+18=36 36/3=12

You might be interested in

-30 = -16 + N what is he answer to this

marta [7]

Answer:

Step-by-step explanation:

To solve for the given variable $N$ , we need to get $N$ on one side of the equation by itself. To do so, we need to remove the -16 that is on the same side of the variable.

To get rid of the -16, we can add a 16 to that side of the equation since $-16 + 16 = 0$ , which will get $N$ by itself; however, if we add -16 to one side of the equation, we must add it to both sides of the equation:

$-30 + 16 = -16 + 16 + N$

$-14 = N$

4 0

3 years ago

Is the live tutoring over video, or do you type the question and send it to the tutor please explain?

igor_vitrenko [27]

Answer:

It can be either one, if you prefer reading you can ask questions through text, if you prefer talking verbally then I'd say over video is best.

4 0

3 years ago

A disk with radius 3 units is inscribed in a regular hexagon. Find the approximate area of the inscribed disk using the regular

grigory [225]

Answer:33

Step-by-step explanation:

6 0

3 years ago

The quotient of a secret number and 4 is 9

Anna [14]

Let's call the 'secret number' x.

A quotient is basically a Dividend/Divisor. If the Divisor is 4, we need to find the dividend, which is x.

Therefore:
x/4=9
We need to isolate the variable by the multiplication property of equality.
x=36.

As a result, the "secret number" is 36

4 0

3 years ago

Find dy/dx by implicit differentiation. y cos x = 5x2 + 3y2

lbvjy [14]

Step 1:
Start by putting $\frac{d}{dx}$ in front of each term

$\frac{d}{dx}[y cos x]= \frac{d}{dx}[5x^2]+ \frac{d}{dx}[ 3y^2]$
-----------------------------------------------------------------------------------------------------------------
Step 2:

Deal with the terms in 'x' and the constant terms
$\frac{d}{dx}[ycosx]= 10x+ \frac{d}{dx} [3y^2]$
----------------------------------------------------------------------------------------------------------------
Step 3:

Use the chain rule for the terms in 'y'
$\frac{d}{dx}[ycosx]=10x+6y \frac{dy}{dx}$
--------------------------------------------------------------------------------------------------------------
Step 4:

Use the product rule on the term in 'x' and 'y'
$(y) \frac{d}{dx} cos x+(cos x) \frac{d}{dx}y =10x+6y \frac{dy}{dx}
$
$y(-siny)+(cosx) \frac{dy}{dx} =10x+6y \frac{dy}{dx}$
--------------------------------------------------------------------------------------------------------------

Step 5:

Rearrange to make $\frac{dy}{dx}$ the subject
$-y sin(y)+cos(x) \frac{dy}{dx} =10x+6y \frac{dy}{dx}$
$cos(x) \frac{dy}{dx}-6y \frac{dy}{dx}=10x+y sin(y)$
$[cos(x) - 6y] \frac{dy}{dx}=10x + y sin(y)$
$\frac{dy}{dx}= \frac{10x+ysin(y)}{cos(x)-6y}$ ⇒ Final Answer

5 0

4 years ago