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Paha777 [63]
3 years ago
9

Help me In sick and don’t feel like doing their rn tbh

Mathematics
1 answer:
castortr0y [4]3 years ago
5 0

Answer:

1.. \:  \: 64 - 40 = 24 \\ so.\% \:  \\  \frac{24}{40}  \times 100 = 60\% \\

............................

1-e

2-h

3-f

4- c

5-d

6-i

7-b

8-a

9-l

10-k

11-j

12-g

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Simplifying expressions:<br> Simplify 22-5(2x+4)
tangare [24]

22-10x-20

=2-10x

=2(1-5x)

hope this helps.

7 0
3 years ago
Read 2 more answers
What is the slope of a line that is parallel to the x-axis? m=
Ludmilka [50]
Parallel to the x-axis and perpendicular to the y-axis: zero
Parallel to the y-axis and perpendicular to the x-axis: undefined
I hope that's right, that's how I remember it
6 0
3 years ago
If the area of a circle measures 25 cm?, what is the circumference of the circle in terms of ?
daser333 [38]
The correct answer is 5 cm
7 0
3 years ago
Find the coordinates of the point (a, b).
Leviafan [203]

Answer:

a = \frac{1}{\sqrt{2} } and b = \frac{\sqrt{2} }{2}

Step-by-step explanation:

As we know, the radius of the unit circle is 1 unit (it is the hypotenuse in the right triangle, the blue line)

We use trigonometric formulas to find out a and b

  • Sin(45) = opposite side / hypotenuse

<=> Sin(45) = b / 1

<=> b= Sin(45)*1 = \frac{\sqrt{2} }{2}

  • Cos(45) = adjacent side / hypotenuse

<=> Cos(45) = a / 1

<=> a =  Cos(45)*1 = \frac{1}{\sqrt{2} }

So: a = \frac{1}{\sqrt{2} } and b = \frac{\sqrt{2} }{2}

5 0
3 years ago
What is the center and radius of a circle whose equation is x2 + y2 -2x -6y -5 = 0?
ddd [48]

x²+y²-2x-6y-5=0

x²-2x+y²-6y=5

x²-2x+1+y²-6y+9=5+1+9

(x-1)²+(y-3)²=15

(x-1)²+(y-3)²=(V15)²

-> centre of the circle: C(-1,-3)

-> radius of the circle: V15

4 0
2 years ago
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