Answer:
729 emails
Step-by-step explanation:
The pattern is to multiply by 3
3*3 = 9
9*3 = 27
27*3 = 81
81*3 = 243
If the pattern continues, Martin will sent on monday:
243*3 = 729
729 emails
Answer:
$2.9
Step-by-step explanation:
Answer: x = 3 and y = 1
Step-by-step explanation:
y = - x + 4 ............... equation 1
y = x - 2 ............. equation 2
Solving the linear equation by substitution method , we have :
substitute equation 2 into equation 1 , that is
x - 2 = - x + 4
Add 2 to both sides , we have
x = -x + 4 + 2
Add x to both sides , we have
2x = 6
divide through by 2
x = 3
Substitute x = 3 into equation 2 to find the value of y , we have
y = x - 2
y = 3 - 2
y = 1
Therefore : x = 3 and y = 1
The equation is (X+9)+6=5
Answer:
Linear function
<h3>

</h3>
Step-by-step explanation:
<h2>

</h2><h3>Linear function</h3>
A linear equation is an equation of a straight line, which means that the degree of a linear equation must be 0 or 1 for each of its variables. In this case, the degree of variable y is 1 and the degree of variable x is 1.
<h2>

</h2><h3>Not linear function</h3>
A linear equation is an equation of a straight line, which means that the degree of a linear equation must be 0 or 1 for each of its variables. In this case, the degree of variable y is 1
, the degrees of the variables in the equation violate the linear equation definition, which means that the equation is not a linear equation.
<h2>

</h2><h3>Not linear function</h3>
A linear equation is an equation of a straight line, which means that the degree of a linear equation must be 0 or 1 for each of its variables. In this case, the degrees of the variables in the equation violate the linear equation definition, which means that the equation is not a linear equation.
<h2>

</h2><h3>Not linear function</h3>
A linear equation is an equation of a straight line, which means that the degree of a linear equation must be 0 or 1 for each of its variables. In this case, the degree of variable y is 1 and the degree of variable x is 2.
<h3>Hope it is helpful...</h3>