I need help ASAP like I might actually fail

Mathematics

1 answer:

natulia [17]3 years ago

8 0

2x + 7 ≤ 3x - 5

Start by keeping the variable x on the left side of the inequality, and move everything else to the right side.

We can do this by subtracting 3x from both sides and subtracting 7 from both sides.

-x ≤ -12

Divide both sides by -1 to make x a positive; when dividing by a negative number you will flip the inequality sign, so ≤ becomes ≥.

x ≥ 12

Possible solutions for x are any number equal to or greater than 12.

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A plain old black witch hat won't be good enough this year, Wanda

Komok [63]

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4 years ago

I need help with question 11 pleaseeeeeee

ikadub [295]

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The area of the triangular base is bh/2 = (9)(12) / 2. There are two of these.
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6 0

3 years ago

Read 2 more answers

Solve the equation.9x^2 + 16 = 0

REY [17]

Step 1

Given;

$9x^2+16=0$

Required: To solve the equation.

Step 2

Solve the equation

$\begin{gathered} 9x^2+16-16=0-16 \\ 9x^2=-16 \\ \frac{9x^2}{9}=\frac{-16}{9} \\ x^2=-\frac{16}{9} \\ \sqrt{x^2}=\pm\sqrt{\frac{-16}{9}} \\ x=\sqrt{-\frac{16}{9}},\:x=-\sqrt{-\frac{16}{9}} \\ x=i\frac{4}{3},\:x=-i\frac{4}{3} \end{gathered}$

Answer;