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Ainat [17]
3 years ago
14

I need help ASAP like I might actually fail

Mathematics
1 answer:
natulia [17]3 years ago
8 0

2x + 7 ≤ 3x - 5

Start by keeping the variable x on the left side of the inequality, and move everything else to the right side.

We can do this by subtracting 3x from both sides and subtracting 7 from both sides.

-x ≤ -12

Divide both sides by -1 to make x a positive; when dividing by a negative number you will flip the inequality sign, so ≤ becomes ≥.

x ≥ 12

Possible solutions for x are any number equal to or greater than 12.

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To factor an expression of the form:

x^2+bx+c

we find two numbers B and C that fulfills the following properties:

\begin{gathered} B+C=b \\ BC=c \end{gathered}

In this case we have b=-4 and c=-12. We can choose B=-6 and C=2. Then we write the expression as:

x^2-4x-12=x^2-6x+2x-12

and we factor the common factors in the first two and last terms:

\begin{gathered} x^2-4x-12=x^2-6x+2x-12 \\ =x(x-6)+2(x-6) \\ =(x+2)(x-6) \end{gathered}

Therefore:

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Step-by-step explanation:

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