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Kipish [7]
4 years ago
14

A random sample of 1000 tulips from a large cultivated field yields 847 purple flowers and 153 pink flowers.

Mathematics
1 answer:
timofeeve [1]4 years ago
4 0

Answer:

The frequency of the purple and pink alleles in this field population are 84.7% and 15.3% respectively.

Step-by-step explanation:

According to the law of large numbers, in probability concept, as we increase the sample size (<em>n</em>), the sample statistic value approaches the value of the population parameter.

For example, as the sample size increases the sample mean (\bar x) approaches the true population mean (<em>μ</em>).

Similarly, as the sample size is increased the the population proportion can be estimated by the sample proportion.

In this case, a random sample of <em>n</em> = 1000 tulips are selected.

Of these 1000 tulips, the number of purple flowers was 847 and the number of pink flower was 153.

Compute the proportion of purple flower as follows:

P(purple)=\frac{847}{1000}=0.847

The frequency of purple flower is 0.847.

Since, the sample size is quite large, this proportion can be used to estimate the true proportion of purple alleles.

Compute the proportion of pink flower as follows:

P(pink)=\frac{153}{1000}=0.153

The frequency of pink flower is 0.153.

Again since, the sample size is quite large, this proportion can be used to estimate the true proportion of pink alleles.

Thus, the frequency of the purple and pink alleles in this field population are 84.7% and 15.3% respectively.

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f(-4) = -4 + 4 = 0

So the graph starts at (-4,0)

Now plug in 3 for x  in f(x) = x+4

f(3) = 3 + 4 = 7

So the first function ends at (3,7)

Second function is f(x) = 2x - 1

We plug in 3 for x  in f(x) = 2x-1

f(3) =2(3)-1 = 5

So the second graph starts at (3,5)

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f(6) =2(6)-1 = 11

So the second graph ends at (6,11)

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The range of the following piece wise function is 0  to 11

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You went to the mall with $52.50. You bought three shirts that each cost x
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1. Construct a table of values of the following functions using the interval of 5
Morgarella [4.7K]

Complete Question:

Construct a table of values of the following functions using the interval of -5 to 5.

g(x) = \frac{x^3 + 3x - 5}{x^2}

Answer:

See Explanation

Step-by-step explanation:

Required

Construct a table with the given interval

When x = -5

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(-5) = \frac{-5^3 + 3(-5) - 5}{-5^2}

g(-5) = \frac{-125 -15 - 5}{25}

g(-5) = \frac{-145}{25}

g(-5) = -5.8

When x = -4

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(-4) = \frac{-4^3 + 3(-4) - 5}{-4^2}

g(-4) = \frac{-64 -12 - 5}{16}

g(-4) = \frac{-81}{16}

g(-4) = -5.0625

When x = -3

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(-3) = \frac{-3^3 + 3(-3) - 5}{-3^2}

g(-3) = \frac{-27 -9 - 5}{9}

g(-3) = \frac{-41}{9}

g(-3) = -4.56

When x = -2

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(-2) = \frac{-2^3 + 3(-2) - 5}{-2^2}

g(-2) = \frac{-8 -6 - 5}{4}

g(-2) = \frac{-19}{4}

g(-2) = -4.75

When x = -1

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(-1) = \frac{-1^3 + 3(-1) - 5}{-1^2}

g(-1) = \frac{-1 + 3 - 5}{1}

g(-1) = \frac{-3}{1}

g(-1) = -3

When x = 0

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(0) = \frac{0^3 + 3(0) - 5}{0^2}

g(0) = \frac{0 + 0 - 5}{0}

g(0) = \frac{- 5}{0}

<em>g(0) = undefined</em>

When x = 1

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(1) = \frac{1^3 + 3(1) - 5}{1^2}

g(1) = \frac{1 + 3 - 5}{1}

g(1) = \frac{-1}{1}

g(1) = 1

When x = 2

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(2) = \frac{2^3 + 3(2) - 5}{2^2}

g(2) = \frac{8 + 6 - 5}{4}

g(2) = \frac{9}{4}

g(2) = 2.25

When x = 3

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(3) = \frac{3^3 + 3(3) - 5}{3^2}

g(3) = \frac{27 + 9 - 5}{9}

g(3) = \frac{31}{9}

g(3) = 3.44

When x = 4

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(4) = \frac{4^3 + 3(4) - 5}{4^2}

g(4) = \frac{64 + 12 - 5}{16}

g(4) = \frac{71}{16}

g(4) = 4.4375

When x = 5

g(x) = \frac{x^3 + 3x - 5}{x^2} becomes

g(5) = \frac{5^3 + 3(5) - 5}{5^2}

g(5) = \frac{125 + 15 - 5}{25}

g(5) = \frac{135}{25}

g(5) = 5.4

<em>Hence, the complete table is:</em>

x  ---- g(x)

-5 --- -5.8

-4 --- -5.0625    

-3 --- -4.56

-2 --- -4.75  

-1 --- -3

0 -- Undefined

1 --- 1

2 -- 2.25

3 --- 3.44

4 --- 4.4375

5 --- 5.4

7 0
3 years ago
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