Answer:
Step-by-step explanation:
Question
Find the perimeter of a triangle with vertices A(2,5) B(2,-2) C(5,-2). Round your answer to the nearest tenth and show your work.
perimeter of a triangle = AB+AC+BC
Using the distance formula
AB = sqrt(-2-5)²+(2-2)²
AB = sqrt(-7)²
AB =sqrt(49)
AB =7
BC = sqrt(-2+2)²+(2-5)²
BC = sqrt(0+3²)
BC =sqrt(9)
BC =3
AC= sqrt(-2-5)²+(2-5)²
AC= sqrt(-7)²+3²
AC =sqrt(49+9)
AC =sqrt58
Perimeter = 10+sqrt58
The property shown there is the distributive property.
It states that a(b + c) = ab + ac
Or a(b - c) = ab - ac
Answer:
2232.48 meters
Step-by-step explanation:
From the diagram:
Radius of semicircle = 74
Length of straightway on each side = 1000
The length of school track:
Straightway on each side = 2 * 1000 m = 2000m
Length of semicircle = πr/2
Length of both semicircle = 2 * 3.142 * 74 /2 = 232.47785
Total Length = ( 2000 + 232.47785) = 2232.48 meters
Hope this helps!
T= -9 :) , because negative divided by a negative is a positive!
Answer:
x=18
Step-by-step explanation:
