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3 years ago

If f(x) = 2x2 + 2 and g(x) = x2 - 1, find (f - g)(x)I

Mathematics

1 answer:

erastovalidia [21]3 years ago

4 0

9514 1404 393

Answer:

C. x^2 + 3

Step-by-step explanation:

Substitute for f(x) and g(x) and simplify.

(f -g)(x) = f(x) -g(x)

(f -g)(x) = (2x^2 +2) -(x^2 -1) = 2x^2 +2 -x^2 +1

(f -g)(x) = x^2 +3

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PLEASE HELP ASAP! The quotient of two rational numbers is positive. What can you conclude about the signs of the dividend and th

Anon25 [30]

Answer:

They either both have to be positive or negative.

Step-by-step explanation:

1 / 1 = 1

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This gets you positive, when both dividend and divisors are positive or negative.

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This gets you negative, when both dividend and divisors are different signs.

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3 years ago

Read 2 more answers

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Travka [436]

Answer:

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Step-by-step explanation:

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2 years ago

What are the solutions to the quadratic equation x? - 16 = 0?

makkiz [27]

Answer:

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3 years ago

If f(x) = 2x2 + 2, find f(5).

nalin [4]

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3 years ago

For the following exercises, determine whether the functions are even, odd, or neither.

stealth61 [152]

Answer:

The solutions of the equation |2 x-3|=17

are x=10

and x=-7

Step-by-step explanation:

Given equations is |2 x-3|=17.

It is required to find out the values of x satisfying the given equation.

To find it out, use the fact that the solution of this type of equation is 2x-3=17.

Or 2x-3=-17 and simplify the equations using simple mathematical operations.

Step 1 of 2

Solve the equation 2x-3=17,

Add 3 on both sides of the equation 2x-3=17,

2x-3+3=17+3

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Divide by 2 on both sides of the equation 2x=20,

$\begin{aligned}&\frac{2 x}{2}=\frac{20}{2} \\&x=10\end{aligned}$

Step 2 of 2

Solve the equation 2x-3=-17,

Add 3 on both sides of the equation 2x-3=-17,

$2 x-3+3=-17+3$\\ $2 x=-14$

Divide by 2 on both sides of the equation 2x=-14,

$\begin{aligned}&\frac{2 x}{2}=\frac{-14}{2} \\&x=-7\end{aligned}$

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2 years ago