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julia-pushkina [17]
3 years ago
6

Help me please help me ​

Mathematics
1 answer:
Tanya [424]3 years ago
7 0

Answer:

Hope this much helps you.

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You divide -16 by 76 and then mutiply your answer by the  number you got
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You need 11.6666666666
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Solve for x. Write both solutions, separated by a comma. 8x^2+7x-1=0
Ivan

Answer:

<h2>x = 1/8 , - 1</h2>

Step-by-step explanation:

8x² + 7x - 1 = 0

Rewrite 7x as a difference

That's

8x² + 8x - x - 1 = 0

Factorize

8x( x + 1) - ( x + 1) = 0

(8x - 1)( x + 1) = 0

8x - 1 = 0 x + 1 =0

8x = 1 x = - 1

x = 1/8

The solutions are

<h3>x = 1/8 , - 1</h3>

Hope this helps you

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3 years ago
Explain what is meant by domain and range.
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Suppose that the functions q and r are defined as follows.
satela [25.4K]

Answer:

(r o g)(2) = 4

(q o r)(2) = 14

Step-by-step explanation:

Given

g(x) = x^2 + 5

r(x) = \sqrt{x + 7}

Solving (a): (r o q)(2)

In function:

(r o g)(x) = r(g(x))

So, first we calculate g(2)

g(x) = x^2 + 5

g(2) = 2^2 + 5

g(2) = 4 + 5

g(2) = 9

Next, we calculate r(g(2))

Substitute 9 for g(2)in r(g(2))

r(q(2)) = r(9)

This gives:

r(x) = \sqrt{x + 7}

r(9) = \sqrt{9 +7{

r(9) = \sqrt{16}{

r(9) = 4

Hence:

(r o g)(2) = 4

Solving (b): (q o r)(2)

So, first we calculate r(2)

r(x) = \sqrt{x + 7}

r(2) = \sqrt{2 + 7}

r(2) = \sqrt{9}

r(2) = 3

Next, we calculate g(r(2))

Substitute 3 for r(2)in g(r(2))

g(r(2)) = g(3)

g(x) = x^2 + 5

g(3) = 3^2 + 5

g(3) = 9 + 5

g(3) = 14

Hence:

(q o r)(2) = 14

8 0
3 years ago
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