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3 years ago

If two 6-sides dice are rolled, what is the probability that they will land on double fours?

Mathematics

2 answers:

ch4aika [34]3 years ago

7 0

Answer:96

Step-by-step explanation:Since 6 times 2 is 12.If they roll 4 double times then it’s 96!

Olenka [21]3 years ago

3 0

the answer is 96 :))))))

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Which expression is equivalent to 30(1/2x - 2) plus 40(3/4y-4)

nirvana33 [79]

Answer:

225

Step-by-step explanation:

7 0

4 years ago

an equation of a circle is x2 + y2 + 10x – 6y + 18 = 0. . . . A.Show all your work in determining the center and radius of this

MariettaO [177]

A circle is a set of points in a plane equidistant from a fixed point. It has a general formula of x² + y² = r². This is if the center is at the origin. However, if the center at point h and k, the equation becomes (x-h)² + (y-k)² = r².

We write the given equation in the form (x-h)² + (y-k)² = r² by completing the square.

x² + y² + 10x – 6y + 18 = 0

(x² + 10x + 25 )+ (y² - 6y + 9) = −18 + 25 + 9 = 16
(x + 5)² + (y + 3)² = (4)²

Therefore,

center = (-5, -5)
radius = 4

7 0

4 years ago

Given that 2x – 2y = 23

lidiya [134]

Answer:

x = 41/2

Step-by-step explanation:

I am assuming that we are finding 'x' when y = 9.

$2x-2y=23\\\\2x-2(9)=23\\\\2x-18=23\\\\2x-18+18=23+18\\\\2x=41\\\\\frac{2x=41}{2}\\\\\boxed{x=\frac{41}{2}}$

Hope this helps!

8 0

3 years ago

Read 2 more answers

How to evaluate F/G(x) if f(x)=x²-2x , g(x) = x+9

tiny-mole [99]

Answer:

$f/g\textrm{ }(x)=\frac{x^{2}-2x}{x+9}$

Step-by-step explanation:

Given:

$f(x)=x^{2}-2x$ , $g(x)=x+9$

$f/g\textrm{ }(x)$ is nothing but dividing $f(x)$ by $g(x)$

Therefore, $f/g\textrm{ }(x)$ is given as:

$f/g\textrm{ }(x)=\frac{f(x)}{g(x)}\\f/g(x)=\frac{x^{2}-2x}{x+9}$

6 0

3 years ago

The twice–differentiable function f is defined for all real numbers and satisfies the following conditions: f(0)=3 f′(0)=5 f″(0)

Vladimir79 [104]

$g(x)=e^{ax}+f(x)\implies g'(x)=ae^{ax}+f'(x)\implies g''(x)=a^2e^{ax}+f''(x)$

Given that $f'(0)=5$ and $f''(0)=7$ , it follows that

$g'(0)=a+5$

$g''(0)=a^2+7$

###

$h(x)=\cos(kx)f(x)+\sin x\implies h'(x)=-k\sin(kx)f(x)+\cos(kx)f'(x)+\cos x$

When $x=0$ , we have

$h(0)=\cos0f(0)+\sin0=f(0)=3$

The slope of the line tangent to $h(x)$ at (0, 3) has slope $h'(0)$ ,

$h'(0)=-k\sin0f(0)+\cos0f'(0)+\cos0=5+1=6$

Then the tangent line at this point has equation

$y-3=6(x-0)\implies y=6x+3$

###

Differentiating both sides of

$4x^2+y^2=48+2xy$

with respect to $x$ yields

$8x+2y\dfrac{\mathrm dy}{\mathrm dx}=2y+2x\dfrac{\mathrm dy}{\mathrm dx}$

$\implies(2y-2x)\dfrac{\mathrm dy}{\mathrm dx}=2y-8x$

$\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y-4x}{y-x}$

On this curve, when $x=2$ we have

$4(2)^2+y^2=48+2(2)y\implies y^2-4y-32=(y-8)(y+4)=0\implies y=8$

(ignoring the negative solution because we don't care about it)

The tangent to this curve at the point $(x,y)$ has slope $\dfrac{\mathrm dy}{\mathrm dx}$ . This tangent line is horizontal when its slope is 0. This happens for

$\dfrac{y-4x}{y-x}=0\implies y-4x=0\implies y=4x$

and when $x=2$ , there is a horizontal tangent line to the curve at the point (2, 8).

5 0

3 years ago