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sveticcg [70]
3 years ago
6

If two 6-sides dice are rolled, what is the probability that they will land on double fours?

Mathematics
2 answers:
ch4aika [34]3 years ago
7 0

Answer:96

Step-by-step explanation:Since 6 times 2 is 12.If they roll 4 double times then it’s 96!

Olenka [21]3 years ago
3 0

the answer is 96 :))))))

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Which expression is equivalent to 30(1/2x - 2) plus 40(3/4y-4)
nirvana33 [79]

Answer:

225

Step-by-step explanation:

7 0
4 years ago
an equation of a circle is x2 + y2 + 10x – 6y + 18 = 0. . . . A.Show all your work in determining the center and radius of this
MariettaO [177]

A circle is a set of points in a plane equidistant from a fixed point. It has a general formula of x² + y² = r². This is if the center is at the origin. However, if the center at point h and k, the equation becomes (x-h)² + (y-k)² = r².<span>

We write the given equation in the form (x-h)² + (y-k)² = r² by completing the square.
</span>

<span>x</span>²<span> + y</span>²<span> + 10x – 6y + 18 = 0</span>

<span> (x² + 10x + 25 )+ (y² - 6y + 9) = −18 + 25 + 9 = 16
(x + 5)² + (y + 3)² = (4)²

Therefore,

center = (-5, -5)
radius = 4</span>

7 0
4 years ago
Given that 2x – 2y = 23
lidiya [134]

Answer:

x = 41/2

Step-by-step explanation:

I am assuming that we are finding 'x' when y = 9.

2x-2y=23\\\\2x-2(9)=23\\\\2x-18=23\\\\2x-18+18=23+18\\\\2x=41\\\\\frac{2x=41}{2}\\\\\boxed{x=\frac{41}{2}}

Hope this helps!

8 0
3 years ago
Read 2 more answers
How to evaluate F/G(x) if f(x)=x²-2x , g(x) = x+9​
tiny-mole [99]

Answer:

f/g\textrm{ }(x)=\frac{x^{2}-2x}{x+9}

Step-by-step explanation:

Given:

f(x)=x^{2}-2x, g(x)=x+9

f/g\textrm{ }(x) is nothing but dividing f(x) by g(x)

Therefore, f/g\textrm{ }(x) is given as:

f/g\textrm{ }(x)=\frac{f(x)}{g(x)}\\f/g(x)=\frac{x^{2}-2x}{x+9}

6 0
3 years ago
The twice–differentiable function f is defined for all real numbers and satisfies the following conditions: f(0)=3 f′(0)=5 f″(0)
Vladimir79 [104]

g(x)=e^{ax}+f(x)\implies g'(x)=ae^{ax}+f'(x)\implies g''(x)=a^2e^{ax}+f''(x)

Given that f'(0)=5 and f''(0)=7, it follows that

g'(0)=a+5

g''(0)=a^2+7

###

h(x)=\cos(kx)f(x)+\sin x\implies h'(x)=-k\sin(kx)f(x)+\cos(kx)f'(x)+\cos x

When x=0, we have

h(0)=\cos0f(0)+\sin0=f(0)=3

The slope of the line tangent to h(x) at (0, 3) has slope h'(0),

h'(0)=-k\sin0f(0)+\cos0f'(0)+\cos0=5+1=6

Then the tangent line at this point has equation

y-3=6(x-0)\implies y=6x+3

###

Differentiating both sides of

4x^2+y^2=48+2xy

with respect to x yields

8x+2y\dfrac{\mathrm dy}{\mathrm dx}=2y+2x\dfrac{\mathrm dy}{\mathrm dx}

\implies(2y-2x)\dfrac{\mathrm dy}{\mathrm dx}=2y-8x

\implies\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y-4x}{y-x}

On this curve, when x=2 we have

4(2)^2+y^2=48+2(2)y\implies y^2-4y-32=(y-8)(y+4)=0\implies y=8

(ignoring the negative solution because we don't care about it)

The tangent to this curve at the point (x,y) has slope \dfrac{\mathrm dy}{\mathrm dx}. This tangent line is horizontal when its slope is 0. This happens for

\dfrac{y-4x}{y-x}=0\implies y-4x=0\implies y=4x

and when x=2, there is a horizontal tangent line to the curve at the point (2, 8).

5 0
3 years ago
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