Answer:
Below.
Step-by-step explanation:
I won't do all of these for you but I'll show you the general method.
First write each number as prime factors.
For example number 7:
LCM of 24 and 34.
24 = 2 * 2 * 2 * 3
34 = 2 * 17
The LCM is the multiple of all these factors EXCEPT if there is a duplicate number you only use it once.
There is one duplicate here - the 2 ( in bold) so we only use this once.
So the LCM = 2 * 2 * 2 * 3 * 17 = 408.
Number 1:
13, 25
13 = 13
25 = 5 * 5
There are no duplicates so the LCM = 13 * 5 * 5 = 325.
Number 18:
15, 84
15 = 3 * 5
84 = 2 * 2 * 3 * 7
Number 3 is common to both sets so it is only used once:
LCM = 2 * 2 * 3 * 5 * 7 = 420.
Number 40:
18, 48
18 = 2 * 3 * 3
48 = 2 * 2 * 2 * 2 * 3
There are 2 sets of duplicates here, 2 and 3 .
LCM = 2 * 2 * 2* 2 * 3 * 3 = 144.
Replace x and y with the given values and solve the equations:
A) 3(5) + 2 = 17
B) 2(5)^2 = 50
C) (5-2)^2 = 9
The equation is y=-2/5x+7 3/5
I think it'd be 1 because well all you are doing is multiplying 1, 8 times. That is only if you meant the I to be 1.
