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fenix001 [56]
4 years ago
10

A compound of two chemicals is mixed in a ratio of 3:12 if there are 45L of the compound how much of each chemical is in the mix

ture
Mathematics
2 answers:
zzz [600]4 years ago
6 0

3x+12x=45

15x=45

x=3

the first chemical is 3*3 or 9 L

the second chemical is 12*3 = 36 L

Zielflug [23.3K]4 years ago
6 0

Answer:

We need 9L from one chemical and 12L from the other.

Step-by-step explanation:

What 3:12 means is that if you add 3L from one chemical(lets say A chemical) then you will have to add 12L from the other chemical (lets say B chemical) to make the compound.

Now Lets take that you added xL of chemical A to make 45L of the compound.

So if add 3L from chemical A you have to add 12L of chemical B, so if you add xL of A then how many liters of B do you need?

⇒\frac{12}{3} *x

=4x

So you will need 4xL of chemical B.

Now we can write an equation for the total amount of compound B as,

⇒x+4x=45

5x=45

x=9

Therefore,

We need 9L of chemical A, and

We need 36L of chemical B



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Step-by-step explanation:

From the question given above, the following data were obtained:

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