Answer:
A) Become 1/ 2 of its original value.
B) Become one-half of its original value.
Explanation:
As we know that heat transfer trough the wall of thickness t given as
Where
K=Thermal conductivity of the wall
A= Cross sectional area of the wall
t=Thickness of the wall
ΔT=temperature difference across the wall surfaces.
When the thickness become double ,lets sat t' = 2 t
Then new heat transfer
Therefore the new heat transfer become half of the original.
Answer:
Explanation:
Velocity is defined as the rate of change of displacement.
velocity is a vector quantity, that means it requires both magnitude and direction to completely explain the velocity.
For example, the velocity is 5 ms due east, it means an object is moving with speed 5 ms in the direction of east. We can say that the object covers the displacement of 5 m in one second due east.
Answer:
Both its temperature and its thermal energy will increase.
Explanation:
Objects are made up of particles. For example, water is made up of water molecules. The kinetic energy of a particle of mass and velocity is equal to ,
- The thermal energy of an object measures the total kinetic energy of all its particles.
- On the other hand, the temperature of that object measures the average kinetic energy of all these particles.
Water in that pot gains energy when the pot is heated. That would increase the total kinetic energy of these water molecules.
What about temperature? Assume that the number of water particles in the pot stays the same- In other words, assume that water in the pot does not evaporate. As the total kinetic energy of these water molecules increase, their average kinetic energy would also increase. As a result, it would appear that the temperature of water in that pot has increased.
Answer:
11 m/s
Explanation:
The motion of the box is a uniformly accelerated motion (=constant acceleration), therefore we can use the following suvat equation:
where:
v is the final velocity
u is the initial velocity
a is the acceleration
t is the time
For the box in this problem, we have:
u = 3 m/s is the initial velocity
is the acceleration
t = 4 s is the time interval
Solving for v, we find the velocity after 4 seconds:
Answer:
Hello your question is poorly written below is the complete question
Suppose the battery in a clock wears out after moving Ten thousand coulombs of charge through the clock at a rate of 0.5 Ma how long did the clock run on does battery and how many electrons per second slowed?
answer :
a) 231.48 days
b) n = 3.125 * 10^15
Explanation:
Battery moved 10,000 coulombs
current rate = 0.5 mA
<u>A) Determine how long the clock run on the battery. use the relation below</u>
q = i * t ----- ( 1 )
q = charge , i = current , t = time
10000 = 0.5 * 10^-3 * t
hence t = 2 * 10^7 secs
hence the time = 231.48 days
<u>B) Determine how many electrons per second flowed </u>
q = n*e ------ ( 2 )
n = number of electrons
e = 1.6 * 10^-19
q = 0.5 * 10^-3 coulomb ( charge flowing per electron )
back to equation 2
n ( number of electrons ) = q / e = ( 0.5 * 10^-3 ) / ( 1.6 * 10^-19 )
hence : n = 3.125 * 10^15