The answer is Fuse. Circuit breakers and fuses are generally known as "Overload Protection Devices. The difference between a fuse and a circuit breaker is that a fuse is a one time circuit element while a circuit breaker is a multiple use device. If you were designing a circuit for a reading lamp, a fuse would do. Since almost all household installed a circuit breaker for outlets, etc,
The final velocity of the 14 kg object is 1.6 m/s in the same direction
Explanation:
We can solve this problem by using the law of conservation of momentum: the total momentum of the system must be conserved before and after the collision. Therefore, we can write

where:
is the mass of the first object
is the initial velocity of the first object
is the final velocity of the first object
is the mass of the second object
is the initial velocity of the second object
is the final velocity of the second object
Re-arranging the equation and substituting the values, we find:

And the direction is the same as the initial direction, since it has the same sign.
Learn more about conservation of momentum:
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Answer:
The mass of the skateboard is 1.25 kg.
Explanation:
We have,
Mass of dog, m = 5 kg
Initial speed of dog, u = 2.5 m/s
Initial speed of skateboard, u' = 0 (at rest)
The dog jumps onto the skateboard and both the dog and skateboard move with a speed of 2.00 m/s. It is the common speed of the dog +skateboard, V = 2 m/s. We need to find the mass of the skateboard. Using conservation of momentum as :

m' is mass of skateboard

So, the mass of the skateboard is 1.25 kg.
Complete Question
The complete question is shown on the first uploaded image
Answer:
The uncertainty in inverse frequency is ![\Delta [\frac{1}{w} ]= \frac{3}{2000} \ s](https://tex.z-dn.net/?f=%5CDelta%20%20%5B%5Cfrac%7B1%7D%7Bw%7D%20%5D%3D%20%20%5Cfrac%7B3%7D%7B2000%7D%20%5C%20s)
Explanation:
From the question we are told that
The value of the proportionality constant is 
The strength of the magnetic field is 
The change in this strength of magnetic field is
The magnetic field is given as

Where
is frequency
The uncertainty or error of the field is given as
![\Delta B = \frac{k }{[\frac{1}{w}^]^2 } \Delta [\frac{1}{w} ]](https://tex.z-dn.net/?f=%5CDelta%20%20B%20%20%3D%20%20%5Cfrac%7Bk%20%7D%7B%5B%5Cfrac%7B1%7D%7Bw%7D%5E%5D%5E2%20%7D%20%20%5CDelta%20%5B%5Cfrac%7B1%7D%7Bw%7D%20%5D)
The uncertainty in inverse frequency is given as
![\Delta [\frac{1}{w} ] = \frac{\Delta B}{k [\frac{1}{w^2} ]}](https://tex.z-dn.net/?f=%5CDelta%20%20%5B%5Cfrac%7B1%7D%7Bw%7D%20%5D%20%20%3D%20%5Cfrac%7B%5CDelta%20B%7D%7Bk%20%5B%5Cfrac%7B1%7D%7Bw%5E2%7D%20%5D%7D)
![\Delta [\frac{1}{w} ]= \frac{\Delta B}{k (B)^2 }](https://tex.z-dn.net/?f=%5CDelta%20%20%5B%5Cfrac%7B1%7D%7Bw%7D%20%5D%3D%20%20%5Cfrac%7B%5CDelta%20B%7D%7Bk%20%28B%29%5E2%20%7D)
substituting values
![\Delta [\frac{1}{w} ]= \frac{3}{5 (20)^2 }](https://tex.z-dn.net/?f=%5CDelta%20%20%5B%5Cfrac%7B1%7D%7Bw%7D%20%5D%3D%20%20%5Cfrac%7B3%7D%7B5%20%2820%29%5E2%20%7D)
![\Delta [\frac{1}{w} ]= \frac{3}{2000} \ s](https://tex.z-dn.net/?f=%5CDelta%20%20%5B%5Cfrac%7B1%7D%7Bw%7D%20%5D%3D%20%20%5Cfrac%7B3%7D%7B2000%7D%20%5C%20s)
They are positive and remain inside the nucleus.