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beks73 [17]
3 years ago
10

Suppose the battery in a clock wears out after moving thousand coulombs of charge through the clock at a rate of 0.5 Ma how long

did the clock run on does battery and how many electrons per second slowed?
Physics
1 answer:
Ksivusya [100]3 years ago
8 0

Answer:

Hello your question is poorly written below is the complete question

Suppose the battery in a clock wears out after moving Ten thousand coulombs of charge through the clock at a rate of 0.5 Ma how long did the clock run on does battery and how many electrons per second slowed?

answer :

a) 231.48 days

b) n = 3.125 * 10^15

Explanation:

Battery moved 10,000 coulombs

current rate = 0.5 mA

<u>A) Determine how long the clock run on the battery. use the relation below</u>

q = i * t ----- ( 1 )

q = charge , i = current , t = time

10000 = 0.5 * 10^-3 * t

hence  t = 2 * 10^7 secs

hence the time = 231.48  days

<u>B) Determine how many electrons per second flowed </u>

q = n*e ------ ( 2 )

n = number of electrons

e = 1.6 * 10^-19

q = 0.5 * 10^-3 coulomb ( charge flowing per electron )

back to equation 2

n ( number of electrons ) = q / e = ( 0.5 * 10^-3 ) / ( 1.6 * 10^-19 )

hence : n = 3.125 * 10^15

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A 14-kg object moving with a constant velocity
natta225 [31]

The final velocity of the 14 kg object is 1.6 m/s in the same direction

Explanation:

We can solve this problem by using the law of conservation of momentum: the total momentum of the system must be conserved before and after the collision. Therefore, we can write

p_i = p_f\\m_1 u_1 + m_2 u_2 = m_1 v_1 + m_2 v_2

where:

m_1 = 14 kg is the mass of the first object

u_1 = 5.0 m/s is the initial velocity of the first object

v_1 is the final velocity of the first object

m_2 = 8.0 kg is the mass of the second object

u_2 = 3.0 m/s is the initial velocity of the second object

v_2 = 9.0 m/s is the final velocity of the second object

Re-arranging the equation and substituting the values, we find:

v_1 = \frac{m_1 u_1 + m_2 u_2 - m_2 v_2}{m_1}=\frac{(14)(5.0)+(8.0)(3.0)-(8.0)(9.0)}{14}=1.6 m/s

And the direction is the same as the initial direction, since it has the same sign.

Learn more about conservation of momentum:

brainly.com/question/7973509

brainly.com/question/6573742

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A 5.00 kg dog runs towards a skateboard with a speed of 2.50 m/s. The skateboard is initially at rest. The dog jumps onto the sk
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Answer:

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Explanation:

We have,

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Initial speed of skateboard, u' = 0 (at rest)

The dog jumps onto the skateboard and both the dog and skateboard move with a speed of 2.00 m/s. It is the common speed of the dog +skateboard, V = 2 m/s. We need to find the mass of the skateboard. Using conservation of momentum as :

mu+m'u'=(m+m')V

m' is mass of skateboard

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The frequency of the applied RF signal used to excite spins is directly proportional to the magnitude of the static magnetic fie
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Complete Question

The complete question is shown on the first uploaded image  

Answer:

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Explanation:

From the question we are told that

   The value of the proportionality constant is  k  = 5  \frac{Hz }{T}

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The magnetic field is given as

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Where w is frequency

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substituting values

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