Yes, all of your choices are correct.
First, let us define our variables.
Let
x = age of the father
y = age of the son
z = age of the daughter
5 years ago..
(x – 5) = age of the father
(y – 5) = age of the son
(z – 5) = age of the daughter
After 18 years...
(x + 18) = age of the father
(y + 18) = age of the son
(z +18) = age of the daughter
From the first condition
y = z + 5 à
eqn 1
5 years ago
(x-5) = 23 + (y-5) + (z-5)
x –y –z = 18 à
eqn 2
after 18 years
(x+18) = 17*[(y +18 –z – 18)]
x – 17y + 17z = -18 à
eqn 3
solving the 3 equations simultaneously
x = 67
y = 27
z = 22
Answer:
1 62
Step-by-step explanation:
Answer:
Step-by-step explanation:
Information given
n=370 represent the sample selected
estimated proportion of readers owned a laptop
is the value that we want to test
z would represent the statistic
represent the p value
Creating the hypothesis
We need to conduct a hypothesis in order to test if the true proportion of readers owned a laptop is different from 0.45, the system of hypothesis are:
Null hypothesis:
Alternative hypothesis:
The statistic is:
(1)
Replacing we got:
Calculating the p value
We have a bilateral test so then the p value would be:
If 93% of the bar is silver, then the bar is 0.93*8.15 ounces of silver. Solving that makes there 7.58ish ounces of silver in the bar