Answer:
Option: C is the correct answer.
C. Periodic with period 4 and amplitude of about 15.
Step-by-step explanation:
We are given the table of values as:
Hour 1 -- 2 -- 3 -- 4 -- 5 -- 6 -- 7 -- 8 -- 9 -- 10 -- 11
Number 24-41-10-32-26-38-9-31-25-39-12
of boats
As we could see that after every 4 value the values are approximately repeating.
Hence,the data set is approximately periodic.
Also, the amplitude is calculated as:
Average of the maximum and minimum value of each set
We divide the set into 3 sets as follows:
Hour 1 2 3 4
Number of boat 24 41 10 32
Here we have amplitude as:
(41-10)/2=15.5
Hour 5 6 7 8
Number of boat 26 38 9 31
Amplitude is:
(38-9)/2=14.5
Hour 9 10 11 12
Number of boat 25 39 12
Amplitude is:
(39-12)/2=13.5
Hence, we see that the amplitude is about 15.
Answer:
2x - 10 = 10 - 3x
Simplifying
2x + -10 = 10 + -3x
Reorder the terms:
-10 + 2x = 10 + -3x
Solving
-10 + 2x = 10 + -3x
Solving for variable 'x'.
Move all terms containing x to the left, all other terms to the right.
Add '3x' to each side of the equation.
-10 + 2x + 3x = 10 + -3x + 3x
Combine like terms: 2x + 3x = 5x
-10 + 5x = 10 + -3x + 3x
Combine like terms: -3x + 3x = 0
-10 + 5x = 10 + 0
-10 + 5x = 10
Add '10' to each side of the equation.
-10 + 10 + 5x = 10 + 10
Combine like terms: -10 + 10 = 0
0 + 5x = 10 + 10
5x = 10 + 10
Combine like terms: 10 + 10 = 20
5x = 20
Divide each side by '5'.
x = 4
Simplifying
x = 4
The answer
<span>the amount of gold per cubic meter can be found by the ratio
0.78 g /1 </span><span>.5 cubic meters = 0.52 g / cubic meter,
proof
it was said </span><span>the amount of gold per cubic meter (Density)</span>
Answer:
2x^3-11x^2+16x-3
Step-by-step explanation:
Multiply x to all the other factors in the second parenthesis
Multiply -3 to all the other factors in the second parenthesis
