It's False; an octagon has 8 vertices. When you remove the starting vertex and the two adjacent vertices we're left with 5 possible diagonals
Factor out the GCF, which is 4.... 4(4a+3b)
His brothers have 4 games
He had 10 games
So in total there are 14 games
And if there are 2 cases and each one had the same amount, then in each one there would be 14÷2=7
In each case, there are 7 games.
The factor is x-6 since the two factors of your equation are (6x-6) and (x-6)
