I'll use t for the messages Teresa sent, e for messages Eric sent, and r for messages Ryan sent.
Therefore we have, t+e+r=99.
From the text we also know:
e=3r ; r=t+6
If we substitute in the original equation we get:
t+3(t+6)+t+6=99; By simplifying it we get
5t=75 , therefore t=75/5=15.
Since Teresa send 15 messages,Ryan sent 6 more then here, so he send 21. Eric sent three times the
messages Ryan sent so he sent 63 messages. If we add them together 15+21+63, we get the total of 99 messages.
Answer:
e
Step-by-step explanation:
e
Answer:
AC = 6
Step-by-step explanation:
y is the dimension of the horizontal segment (see the attached image).
The hypotenuses are the same dimension, so:
(x+4)^2=(x/2)^2+y^2
(3x-8)^2=(x/2)^2+y^2
So,
(x+4)^2 = (3x-8)^2
x+4 = 3x-8
x-3x = -8-4
-2x = -12
x = 6
And x is the dimension of the segment AC.
Answer:
(D) 29.3
Step-by-step explanation:
The answer is all the days added together and then divided by 10.
20+30+40+38+25+22+39+22+26+31=293.
293/10=29.3
Plot the equation. If you wish to solve a polynomial, let y= polynomial and plot the graph. Best set up a table of values first.
Where the graph crosses the x axis there is a solution for x. There are also solutions for other horizontal lines (y values) by looking at intersections of the graph with these lines. This technique works for linear and non linear equations. You can also use graphs to solve 2-variable systems of equations by examining where the graphs intersect one another. The disadvantage is that you may not be able to have sufficient detail for high degrees of accuracy because of the scale of the graph and drawing inaccuracies.
