Answer:
27 tiles
Step-by-step explanation:
First, find the total area of the kitchen.
Use the area formula, A = lw
A = lw
A = (9)(12)
A = 108
So, the area of the kitchen is 108 sq ft
Find the area of the square tiles, using the same formula:
A = lw
A = (2)(2)
A = 4
So, the area of one square tile is 4 sq ft
Find how many tiles they will need to buy by dividing the total area by the area of one tile:
108/4
= 27
So, they will need to buy 27 tiles
Answer: D is the correct answer.
20 people
Reason - following the sequence
Answer:
58.5
Step-by-step explanation:
This expression should be simplified using order of operations. According to order of operations or PEMDAS, complete any numbers in parenthesis then any exponents, multiplication, division, additions and subtraction moving left to right through each operation.
Begin with Parenthesis.
(7+3-4*9) - Multiply first
(7+3-36) - Then add/subtract left to right
10 - 36 = -26
Replace -26 where the parenthesis were in the original expression.
9/4 (-26)
234/4
58.5
Answer:
Let's define the cost of the cheaper game as X, and the cost of the pricer game as Y.
The total cost of both games is:
X + Y
We know that both games cost just above AED 80
Then:
X + Y > AED 80
From this, we want to prove that at least one of the games costed more than AED 40.
Now let's play with the possible prices of X, there are two possible cases:
X is larger than AED 40
X is equal to or smaller than AED 40.
If X is more than AED 40, then we have a game that costed more than AED 40.
If X is less than or equal to AED 40, then:
X ≥ AED 40
Now let's take the maximum value of X in this scenario, this is:
X = AED 40
Replacing this in the first inequality, we get:
X + Y > AED 80
Replacing the value of X we get:
AED 40 + Y > AED 80
Y > AED 80 - AED 40
Y > AED 40
So when X is equal or smaller than AED 40, the value of Y is larger than AED 40.
So we proven that in all the possible cases, at least one of the two games costs more than AED 40.
