Question

Alex is standing 60 feet from the base of a flagpole. He measures the angle of elevation to the top of the pole as 35º. Vera is 36 feet closer to the base of the flagpole on a straight level path. Find the angle of elevation from the point Vera is standing to the top of the flagpole to the nearest tenth of a degree.
Is it 49.4 degrees?

Answer 1

Answer:

49.4 degrees

Step-by-step explanation:

In Triangle AXY,

$Tan 35^0=\frac{|XY|}{60} \\|XY|=60*Tan 35^0=42.01\:feet\\ Therefore, Height of the pole=42.01 \:feet$

We want to determine the angle of elevation from the point Vera is standing to the top of the flagpole, which is the angle at V in the diagram.

In Triangle XVY

|VY|=36 feet

$Tan \theta=\frac{|XY|}{|VY|} \\Tan \theta=\frac{42.01}{36}\\ \theta=arctan(\frac{42.01}{36})\\ \theta=49.4^0$

Therefore, the angle of elevation from the point Vera is standing to the top of the flagpole is 49.4 degree to the nearest tenth of a degree.