True
AUG, as the start codon, is in green and codes for methionine. The three stop codons are UAA, UAG, and UGA. Stop codons encode a release factor, rather than an amino acid, that causes translation to cease.
3 is the correct answer. Let me know if you want me to explain why that is the answer.
Answer:
<em>There is a 25% chance of an offspring having blue eyes.</em>
Explanation:
A punnet square can be described as a diagram which is made to check the outcomes of a cross.
In the scenario discussed in the question, only one trait is being studied. Such a cross is termed as a monohybrid cross.
As both the parents are heterozygous for the trait, hence the punnet square can be made as follows:
B b
B BB Bb
b Bb bb
The results of this punnet square show that:
- <em>there is 25% chance that the offspring will be homozygous for brown eyes.</em>
- <em>there is a 50% chance that the offspring will be heterozygous for brown color.</em>
- <em>there is a 25% chance that the offspring will be homozygous and have blue eyes. </em>
Answer: Expected heterozygous genotype = 2×46 = 92
Explanation:
According to the hypothesis of segregation of paired genes in heterozygous F1 generation crosses produces 1:2:1 genotype ratio. This means that all these three possible genotypes should be produced in the F2 generation meaning that we have 1(Dominant homozygous) :2 (Dominant heterozygous): 1 (Recessive Homozygous).
Phenotypic ratio shared (dominant: recessive) = 154 and 46
If recessive homozygous phenotype = recessive homozygous genotype = 46
The expected dominant heterozygous genotype= 2 × (recessive homozygous genotype)
= 2 × 46 = 92
Evolution is a slow change that occurs over time
Hope this helps
