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3 years ago

Draw a model write an equation and solve

Mathematics

1 answer:

777dan777 [17]3 years ago

8 0

You need a question to solve this problem because without a question, you cant solve it!

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9. A ladder of length 23 feet leans against the side of a building. The angle of elevation of the ladder is 76. Find the distanc

irakobra [83]

<h3>Answer:</h3>

B) 22.32 feet

$\quad\rule{300pt}{1pt}$

<h3>Solution:</h3>

we are given that , a ladder is placed against a side of building , which forms a right angled triangle . We wre given one side of a right angled triangle ( hypotenuse ) as 23 feet and the angle of elevation as 76 ° . We can find the Perpendicular distance from the top of the ladder go to the ground by using the trigonometric identity:

$\qquad\quad\bull ~{\boxed{\bf{ Sin\theta =\dfrac{Perpendicular}{Hypotenuse}}} }~\bull$

Here,

hypotenuse = 23 feet
$\theta$ = 76°
Value of Sin $\theta$ = 0.97
Perpendicular = ?

$\quad\dashrightarrow\quad \sf { sin\theta =\dfrac{P}{H}}$

$\quad\dashrightarrow\quad \sf { sin76° =\dfrac{P}{23}}$

$\quad\dashrightarrow\quad \sf { 0.97=\dfrac{P}{23}}$

$\quad\dashrightarrow\quad \sf {P = 0.97 \times 23 }$

$\quad\dashrightarrow\quad \sf { P = 22.32}$

‎ㅤ‎ㅤ‎ㅤ~Hence, the distance from the top of the ladder to the ground is 22.32 feet !

$\rule{300pt}{2pt}$

4 0

2 years ago

Find the value of x. is this the correct answer?

IgorLugansk [536]

Step-by-step explanation:

what's the radius

need the radius

5 0

2 years ago

All sacks of sugar have the same weight. All sacks of flour also have the same weight, but not necessarily the same as the weigh

BaLLatris [955]

Answer:

The largest possible weight of flour is 11.25 pounds.

Step-by-step explanation:

To start with, we will assume that the weight of 1 sack of sugar = x pounds

We will also assume that the weight of 1 sack of flour = y pounds

So, the weight of 2 sacks of sugar = 2 * (x) = 2x

Same thing goes for the weight of 3 sacks of flour = 3 * (y) = 3y

Supposing that the weight of (2 sacks of sugar + 3 sacks of flour) ≤ 40 pounds

= 2x + 3y ≤ 40............ we'll call that equation 1.

Also, suppose that the weight of ( 1 sack of flour) ≤ 2 sacks of sugar + 5 pounds

= y ≤ 2x + 5........................ we'll call that equation 2

Therefore, we'll solve for the values of x and y in the two equations and we will get:

2x + 3y ≤ 40

y ≤ 2x + 5

Now, substitute the value of y into equation 1

2x + 3y ≤ 40 ⇒ 2x + 3(2x +5) =40

⇒ 2x + 6x + 15= 40

⇒ 8x + 15 = 40

⇒ 8x = 25

⇒ x = 25/8

⇒ x = 3.12

x cannot be more than 3.12 pounds, so we solve for y

Putting the value of x into equation 2, we'll get

⇒ 2y + 5 = 2(3.12) + 5

⇒ y = 11.25 pounds.

So, n cannot be more than 11.25 pounds

8 0

3 years ago

X f(x) = x2 + 4x . x2_4

PtichkaEL [24]

The answer is 1/(x+4)
Explanation:
You would factor out the denominator
So,
(X-4)(x+4)=x^2-16
So, x-4/(x+4)(x-4)
Then x-4 cancels each other out from the numerator and denominator
Leaving 1/x+4

6 0

3 years ago

(12pts) what is the next step multiple choice

egoroff_w [7]

Answer:

I think its D

Step-by-step explanation:

lmk if its wrong

3 0

3 years ago

Read 2 more answers