The ratio of blue paint to yellow paint is 2 : 3.
The total number of blue paint he used on the first and second day is 10.
The number of yellow paint he used on the first and second day is 15.
On the third day, the highest number of can of blue paint he can use is 2
On the third day, the highest number of can of yellow paint he can use is 3.
<h3>What is the highest number of blue and yellow paint he can use?</h3>
The ratio of blue paint to yellow paint can be determined by determining the simplest form of the paints used: 4 : 6 = 2: 3
Total blue paint cans used on the first and second day = 4 + 6 = 10
Blue paint cans remaining = 14 - 10 = 4
Total yellow paint cans used on the first and second day = 6 + 9 = 15 cans
Yellow paint cans remaining = 20 - 15 = 5 cans
Please find attached the questions. To learn more about ratios, please check: brainly.com/question/19711539
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Answer:
D
Step-by-step explanation:
d/dx(8 - 24/x^2) = 48/x^3
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Indefinite integral assuming all variables are real:
integral(-24/x^2 + 8) dx = 8 x + 24/x + constant
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Limit:
lim_(x-> ± ∞) (8 - 24/x^2) = 8
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Answer:
<em>it is False</em>
Step-by-step explanation: <em>i also did this test </em>
18% = 18/100 = 0,18
22000/0,18 = 22000/(18/100) = (22000 . 100)/18 = 1100000/9 = 122222,2222...
So $22,000 divided by 18% is equal to $122.222,22
Answer:
m= 11/ 12
Step-by-step explanation:
hope that really helps