mRNA codons determine which amino acid will be added to the growing polypeptidic chain. tRNA anticodons pair these codons and add the correct amino acid. <em>The </em><em>dipeptide</em><em> formed will be </em><em>Cysteine-Alanine</em><em>.</em>
------------------------------------------
Let us review a few points,
-
In protein synthesis, the ribosome reads mRNA in the 5´ to 3´ direction.
- According to the codons being readen, tRNA transfers the correct amino acids to build the polypeptide chain.
- A codon is a short sequence of three nucleotides that store the genetic information for the aminoacids´ assembly.
- Each codon represents one amino acid used to build the protein.
- Each tRNA has two important sites. One of them that couples with the codon of the mRNA molecule, named anticodon. The other site couples with an amino acid.
- The anticodon is a short sequence of bases that pairs with mRNA codons.
- tRNA adds amino acids following the codons sequence in the mRNA molecule.
- The protein grows from the amino terminus to the carboxy terminus.
- Adenine forms pairs with Uracyl ⇒ A↔U
- Guanine pairs with Cytosine ⇒ C↔G
In the exposed example,
→ mRNA ⇒ codons ⇒ 5'-UGC - GCA-3'
→ tRNA ⇒ anticodons ⇒ ACG CGU
→ proteins ⇒ amino acids ⇒ Cys Ala ⇒ Codon UGC codes for Cysteine
⇒Codon GCA codes for Alanine
So, for the given sequence of mRNA, tRNA anticodons are ACG and CGU. And the added amino acids are <em>Cysteine and Alanine</em>.
----------------------------------------------
Related link: brainly.com/question/10014731?referrer=searchResults
Answer:
anaerobic respiration takes place when you demand your muscles to do vigorous work. normally, aerobic respiration takes place but when energy is needed immediately, anaerobic respiration takes place. during anaerobic respiration,the body produces lactic acid, which leads to the burning sensation. your lungs deliver oxygen to the muscles much slower than the rate you need, since you're putting your muscles through an extensive exercise, and this leads to muscle fatigue.
Answer:
9:3:3:1
Explanation:
If alleles of two genes separate randomly during anaphase-I of meiosis, some new combinations of the alleles are formed in the gametes. A heterozygous genotype for two loci (let's support TtRr) produces a total of four types of gametes in 1:1:1:1 ratio (TR, Tr, tR, and tr). The random fusion of these gametes from two double heterozygous parents (TtRr x TtRr) gives a phenotype ratio of 9:3:3:1. Here, 9/16 F2 progeny exhibit dominant phenotype for both loci while 1/16 exhibits recessive phenotype for both the genes. Rest 3/16 and 3/16 F2 progeny express dominant trait for one gene and recessive for the other.
