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riadik2000 [5.3K]
2 years ago
10

Simplify: x-1/5(x-1)squared

Mathematics
2 answers:
Feliz [49]2 years ago
7 0

Answer:

that's it hope its helpful

gayaneshka [121]2 years ago
5 0

Answer:

\frac{1}{5x-5}

Step-by-step explanation:

=> \frac{x-1}{5(x-1)^2}

=> \frac{x-1}{5(x-1)(x-1)}

<u><em>Cancelling (x-1)</em></u>

=> \frac{1}{5(x-1)}

=> \frac{1}{5x-5}

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What is the domain and range of<br>-2x + 3y= -12​
monitta

Answer:

  "all real numbers"

Step-by-step explanation:

Both the domain and range of any odd-degree polynomial function are "all real numbers." This is a degree 1 function in both x and y, so that description applies.

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3 years ago
Which two equations are equivalent
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A Air Freshener Used 3 3/4 milliliters perfume wanted to make 3 air freshners how many milliliters of perfume woud she use
larisa [96]
1 and a fourth because 3 3/4 devided by three equals 1 1/4
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3 years ago
What is the decimal equivalent of an 11% increase
valentinak56 [21]

Answer:

0.11

Step-by-step explanation:

You would convert the percentage to a fraction. Since the % symbol means 'out of 100', you would put 11 over 100: 11/100.

Then you would convert the fraction to a decimal: 0.11.

An easier way could also be to take the percentage and move it two decimal places to the right.

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I hope this helps!

3 0
3 years ago
A student says that the sum difference, product and quotient of two
anastassius [24]

Answer:

The quotient of two integers may not always be an integer.

Therefore, I do not agree when a student says that the sum difference, product, and quotient of two are always integers.

Step-by-step explanation:

The student is not largely correct!

The sum, difference, and product of two integers is indeed always an integer.

But, the quotient of two integers may not always be an integer.

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i.e.

4/2 = 2

  • But, if we take the quotient of 2 and 3, the result will not be an integer.

i.e.

2/3 = 0.67

Therefore, I do not agree when a student says that the sum difference, product, and quotient of two are always integers.

7 0
2 years ago
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