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hammer [34]
3 years ago
7

Damien has lived in the apartment building for five years. Ken has lived there for 250 weeks. Who has lived in the building long

er? Explain. Make a table to help
Mathematics
2 answers:
11111nata11111 [884]3 years ago
8 0

Answer: Damien has lived in the apartment longer.

Step-by-step explanation: A year is aproxiamtely 52.1429 weeks long. Divide 250 by a years worth of weeks and you get 4.79 years. Damien has lived in the apartment 5 years making him live in the building longer.

snow_lady [41]3 years ago
6 0

Answer: Damien lived in his apartment longer.

Step-by-step explanation: Damien lived in his apartment longer because if you convert five years into weeks you get 260 weeks. 260 weeks is greater than 250 weeks.

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Building a is 271 meters taller than building
kvv77 [185]

Let a and b represent the heights of the corresponding buildings (in meters).

... a = b +271 . . . . . . . a is 271 meters taller than b

... 2b -a = 211 . . . . . . if a is subtracted from twice b, the result is 211

Use the expression for a in the first equation to substitute for a in the second.

... 2b - (b+271) = 211

... b = 482 . . . . . . . . . . . simplify and add 271

... a = b +271 = 753

Building a is 753 meters tall; building b is 482 meters tall.

4 0
3 years ago
What is the value of A when we rewrite... (PLZ HELP QUICK)
Marina86 [1]

Answer:

<h2>\frac{133}{8}</h2>

Step-by-step explanation:

Given,

{( \frac{5}{2} )}^{x}  +  {( \frac{5}{2} )}^{x + 3}

=  {( \frac{5}{2}) }^{x}  +  {( \frac{5}{2}) }^{x}  \times  {( \frac{5}{2} )}^{3}

= ( \frac{5}{2} ) ^{x} (1 +  {( \frac{5}{2} )}^{3}

=  {( \frac{5}{2} )}^{x} (1 +  \frac{125}{8} )

=  {( \frac{5}{2} )}^{x} ( \frac{1 \times 8 + 125}{8} )

=  {( \frac{5}{2}) }^{x} ( \frac{8 + 125}{8} )

{( \frac{5}{2} )}^{x} ( \frac{133}{8} )

Comparing with A • {( \frac{5}{2}) }^{x}

A = \frac{133}{8}

Hope this helps...

Good luck on your assignment...

7 0
2 years ago
Systems of Linear Equations What are the different ways to solve a system of linear equations? When do you get an answer to a sy
Mrac [35]

Answer:

Different ways to solve a system of linear equations:

  • isolate one variable in one equation and replace it in the other equation
  • multiply/divide one equation by a constant and then add/subtract it to the other one, so that only one variable remains
  • graph the equation and look at the intersection point

If you graph the system:

  • there is only one solution if the lines intersects at only one point
  • there is no solution if the lines don't intersect each other (they are parallel)
  • there are infinitely many solutions if the lines overlap each other (they are the same equation multiplied by some constant)

Step-by-step explanation:

1st system

y = -x – 7  

y = 4/3 x – 7  

solution: x= 0, y = 7

2nd system

y = -3x – 5  

y = x + 3  

solution: x = -2, y = 1

3rd system

y = -2x + 5  

y = 1/3 x – 2

solution:  x = 3, y = -1

4th system

3x + 2y = 2  

x + 2y = -2  

solution: x = 2, y = -2

5th system

x + 3y = -9  

2x – y = -4

solution:  x = -3, y = -2

6th system

x – 2y = 2

-x + 4y = -8

solution:  x = -4, y = -3

7th system

5x + y = -2  

x + y = 2

solution: x = -1, y = -3

3 0
3 years ago
Read 2 more answers
What is the smallest multiple 3 and 4 have in common
murzikaleks [220]
Their least common multiple is 12.
8 0
2 years ago
Solve for x.<br> −8x+14≥60 OR −4x+50&lt;58
Reika [66]

Answer: The solution is,

x\leq -\frac{23}{4} or x>-2

Step-by-step explanation:

Given compound inequality,

-8x + 14 ≥ 60 or -4x + 50 < 58,

By the subtraction property of inequality,

-8x + 14 - 14 ≥ 60 - 14 or -4x + 50 - 50  < 58 -50,

-8x ≥ 46 or -4x < 8

By the division property of inequality,

-x \geq \frac{46}{8} or -x < \frac{8}{4}

Using property a > b ⇒ - a < -b,

x\leq -\frac{23}{4} or x>-2

6 0
3 years ago
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