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3 years ago

Why would an IT technician ever have to change out a computer’s motherboard?

2 answers:

7 0

Here are a couple reasons:
Integrated Ports Gone Bad.
Motherboard is fried from electrical charge.
New features of updates.
Hope this helps.

Svetlanka [38]3 years ago

5 0

Answer:

If the Motherboard was shorted out, you would need to change it out then.

If the Capacitor is shorted or it is leaking out acid, if you can't repair it you would then need to replace it.

If the Motherboard itself is cracked.

Dust and debris can make the Motherboard stop working.

If the CPU has fried the motherboard with a max output.

Explanation:

You might be interested in

I'm getting an iphone xr today. what should i do 1st? Any cool fetures? i have a iphone 6 now so its a pretty big upgrade

Sonja [21]

Answer:

I wouldn't get an iphone xr my stepmom had one and the screen started having problems and the apps were glitching.

8 0

2 years ago

Read 2 more answers

Using the scenario below, answer the following questions:

4vir4ik [10]

Answer:

Here is code in java.

import java.util.*;

class Main

{

public static void main (String[] args) throws java.lang.Exception

{

try{

boolean flag=false;

int total_mile=0;

double avg_mile;

// part 1, create and initialize array

int inp[]={2,5,9,11,13,17,20,22,24,26};

System.out.print("miles ran per week: ");

// print the miles per week of train

for(int x=0;x<10;x++)

{

System.out.print(inp[x]+" ");

}

System.out.println();

//part 2, print the value of index 2 in the list

System.out.println("value at index 2: "+inp[2]+" miles");

//part 3, find length of array

System.out.println("list length: "+inp.length);

// part 4, calculate total mile and average

for(int y=0;y<10;y++)

{

total_mile=total_mile+inp[y];

}

System.out.println("total miles ran: "+total_mile+" miles");

avg_mile=total_mile/10.0;

System.out.println("average no of miles ran= "+avg_mile+" miles");

// part 5, check 4 exist in the list or not

for(int k=0;k<10;k++)

{

if(inp[k]==4)

{

flag=true;

break;

}

if(flag)

System.out.println("4 exist in the list.");

else

System.out.println("4 doesn't exists in the list.");

}catch(Exception ex){

return;}

}

Explanation:

Create and initialize array with list value equals to 2 and maximum value 26. Print the miles of each week.Then find the value of miles at index 2 in the list.Next find the length of the array and print it.Calculate total miles ran of 10 weeks.Then calculate the average miles by dividing the total with 10. In the array, check 4 exist or not.

Output:

miles ran per week: 2 5 9 11 13 17 20 22 24 26

value at index 2: 9 miles

list length: 10

total miles ran: 149 miles

average no of miles ran= 14.9 miles

4 doesn't exists

3 0

3 years ago

Assume that a large number of consecutive IP addresses are available starting at 198.16.0.0 and suppose that two organizations,

Fiesta28 [93]

Answer & Explanation:

An IP version 4 address is of the form w.x.y.z/s

where s = subnet mask

w = first 8 bit field, x = 2nd 8 bit field, y = 3rd 8 bit field, and z = 4th 8 bit field

each field has 256 decimal equivalent. that is

binary denary or decimal

11111111 = 2⁸ = 256

w.x.y.z represents

in binary

11111111.11111111.11111111.11111111

in denary

255.255.255.255

note that 255 = 2⁸ - 1 = no of valid hosts/addresses

there are classes of addresses, that is

class A = w.0.0.0 example 10.0.0.0

class B = w.x.0.0 example 172.16.0.0

class C = w.x.y.0 example 198.16.8.1

where w, x, y, z could take numbers from 1 to 255

Now in the question

we were given the ip address : 198.16.0.0 (class B)

address of quantity 4000, 2000, 8000 is possible with a subnet mask of type

255.255.0.0 (denary) or

11111111.11111111.00000000.00000000(binary) where /s = /16 That is no of 1s

In a VLSM (Variable Length Subnet Mask)

Step 1

we convert the number of host/addresses for company A to binary

4000 = 111110100000 = 12 bit

step 2 (subnet mask)

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11110000.000000 /20

now we have added 4 1s in the 3rd field to reserve 12 0s

subnet mask: 255.255.16.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1 1  1  1 1 1 1

128 64 32 16 8 4 2 1

step 3

in the ip network address: 198.16.0.0/19 (subnet representation) we increment this using 16

that is 16 is added to the 3rd field as follows

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.0.1 - 198.16.15.255(last valid IP address)

Company B starts+16: 198.16.16.0 - 198.16.31.255

+16: 198.16.32.0- 198.16.47.255 etc

we repeat the steps for other companies as follows

Company B

Step 1

we convert the number of host/addresses for company B to binary

2000 = 11111010000 = 11 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 11 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11111000.000000 /21

now we have added 5 1s in the third field to reserve 11 0s

subnet mask: 255.255.8.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1 1 1 1  1 1 1

128 64 32 16 8  4 2 1

Step 3

Starting from after the last valid Ip address for company A

in the ip network address: 198.16.16.0/21 (subnet representation) we increment this using 8

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.16.1 - 198.16.23.255(last valid IP address)

Company C starts +16: 198.16.24.0- 198.16.31.255

+16: 198.16.32.0- 198.16.112.255 etc

Company C

Step 1

we convert the number of host/addresses for company C to binary

4000 = 111110100000 = 12 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 12 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11110000.000000 /20

now we have added 4 1s in the 3rd field to reserve 12 0s

subnet mask: 255.255.16.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1 1 1 1 1 1 1

128 64 32 16 8 4 2 1

Step 3

Starting from after the last valid ip address for company B

in the ip network address: 198.16.24.0/20 (subnet representation) we increment this using 16

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.24.1 - 198.16.39.255(last valid IP address)

Company C starts +16: 198.16.40.0- 198.16.55.255

+16: 198.16.56.0- 198.16.71.255 etc

Company D

Step 1

we convert the number of host/addresses for company D to binary

8000 = 1111101000000 = 13 bit

Step 2

vary the fixed subnet mask to reserve zeros (0s) for the 13 bit above

fixed subnet mask: 11111111.11111111.00000000.00000000 /16

variable subnet mask: 11111111.11111111.11100000.000000 /19

now we have added 3 1s in the 3rd field to reserve 13 0s

subnet mask: 255.255.32.0 (where the 1s in each field represent a denary number as follows)

1st 1 = 128, 2nd 1 = 64 as follows

1 1  1  1 1 1 1 1

128 64 32  16 8 4 2 1

Step 3

Starting from after the last valid ip address for company C

in the ip network address: 198.16.40.0/20 (subnet representation) we increment this using 32

That means the ist Valid Ip address starts from

Ist valid Ip add: 198.16.40.1 - 198.16.71.255(last valid IP address)

Company C starts +16: 198.16.72.0- 198.16.103.255

+16: 198.16.104.0- 198.16.136.255 etc

5 0

3 years ago

Everfi module 7 answers

Nat2105 [25]

What is the question?

7 0

2 years ago

Flesh out the body of the print_seconds function so that it prints the total amount of seconds given the hours, minutes, and sec

fiasKO [112]

Answer:

Step by step explanation along with code and output is provided below

Explanation:

#include<iostream>

using namespace std;

// print_seconds function that takes three input arguments hours, mints, and seconds. There are 60*60=3600 seconds in one hour and 60 seconds in a minute. Total seconds will be addition of these three

void print_seconds(int hours, int mints, int seconds)

{

int total_seconds= hours*3600 + mints*60 + seconds;

cout<<"Total seconds are: "<<total_seconds<<endl;

}

// test code

// user inputs hours, minutes and seconds and can also leave any of them by entering 0 that will not effect the program. Then function print_seconds is called to calculate and print the total seconds.

int main()

{

int h,m,s;

cout<<"enter hours if any or enter 0"<<endl;

cin>>h;

cout<<"enter mints if any or enter 0"<<endl;

cin>>m;

cout<<"enter seconds if any or enter 0"<<endl;

cin>>s;

print_seconds(h,m,s);

return 0;

}

Output:

enter hours if any or enter 0

enter mints if any or enter 0

enter seconds if any or enter 0

Total seconds are: 8710

8 0

3 years ago