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Leokris [45]
1 year ago
13

Below you will find the requirements to identify the Account Diversity Grade of a user. Read the requirements carefully and iden

tify what test users you need to setup in order to completely test and make sure all the below requirements are covered. (Note: you should identify the optimum (minimum) number of users needed to test all of the requirements)
Requirements:

A user can have different types of loan accounts. Now we grade a user’s Account Diversity based on two factors.

1) loanTypeCount

2) totalAccounts

loanTypeCount = the number of different (distinct) LoanType values for all accounts that the user has.

However do not include LoanType = Unknown & Collections but include all others

Applicable values for LoanType are ( Home Loan, Heloc, Credit Card, Car Loan, Collections, Unknown)

totalAccounts = total number of loan accounts user has (do not include LoanType = Unknown & Collections but include all others)

example-> if user has 3 credit cards and 2 home loans and 1 Collection account, then totalAccounts = 5 and loanTypeCount = 2)

The logic to determine accountDiversityGrade is the following:

If totalAccounts> 20 or loanTypeCount >= 4, accountDiversityGrade = A

Else if totalAccounts> 10 or loanTypeCount = 3, accountDiversityGrade = B

Else if totalAccounts>= 5 or loanTypeCount= 2, accountDiversityGrade = C

Else if totalAccounts > 0 or loanTypeCount = 1, accountDiversityGrade = D

Else accountDiversityGrade=null (n/a)
Computers and Technology
1 answer:
igomit [66]1 year ago
8 0

The technique I used to test the requirement is equivalence partitioning.

<h3>Equivalence Partitioning-</h3>

Generic test data is considered where all the test data satisfies the conditions provided in the problem. Such that,

- ADGrade A --> TA=25 LC=5

- ADGrade B --> TA=20, LC=3

- ADGrade C --> TA=8 LC=2

- ADGrade D --> TA=2, LC=1

- ADGrade null (n/a)—> TA=0, LC=0

Where:

  • TA represents totalAccounts,
  • LC represents loanTypeCount,
  • ADGrade represents accountDiversityGrade

If we are to combine the test data collected above, we would obtain the entire set of test data.

With this in mind, the minimum number of users that are required for testing the requirement is 5.

Read more about requirement testing here:

brainly.com/question/16147055

#SPJ1

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vesna_86 [32]

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1. Write a class for time objects that store three integer values for hour, minute, and second. Also, write a program to test th
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Answer:

1.

class TIME

{

int hour , min , sec ;

public :

TIME()

{

hour=min=sec=0;

}

TIME( int h , int m , int s )

{

hour = h;

min = m;

sec = s;

}

void change ( int Hour)

{

hour = Hour;

}

void stdtime()

{

if(hour>12)

cout<<"The Standard time is"<<(hour-12)<<":"<<min<<":"<<sec<<"P.M\n";

else

cout<<"The Standard time is"<<hour<<":"<<min<<":"<<sec<<"A.M\n";

}

void miltime()

{

cout<<"The Military time is"<<hour<<":"<<min<<":"<<sec<<" hours\n";

}

};

void main()

{

TIME A , B(13,25,30);

A .stdtime();

A.change(23);

A.miltime();

B.stdtime();

B.change(9);

B.miltime();

}

2.

class elevator

{

int CurrentFloor;

int GoingUp;

int GoingDown;

public:

elevator()

{

CurrentFloor=0;

GoingUp=1;

GoingDown=-1;

}

elevator(int floor)

{

CurrentFloor=floor;

GoingUp=1;

GoingDown=-1;

}

void goUp(int y)

{

if( CurrentFloor>3)

cout<<"\nNO MORE FLOORS\n";

else

CurrentFloor=CurrentFloor+y*GoingUp;

}

void goDown(int x)

{

if(CurrentFloor<0)

cout<<"\nNO MORE FLOORS";

else

CurrentFloor=CurrentFloor+x*GoingDown;

}

};

void main()

{

elevator A(1);

A.goUp(1);

A.goUp(1);

A.goUp(1);

A.goDown(1);

A.goDown(1);

}

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