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KengaRu [80]
3 years ago
10

The arguments in a method call are often referred to as ____ . The variables in the method declaration that accept the values fr

om the actual parameters are ____.
Computers and Technology
1 answer:
Snezhnost [94]3 years ago
4 0

Answer:

The arguments in a method call are often referred to as <u>actual parameters</u>. The variables in the method declaration that accept the values from the actual parameters are <u>formal parameters</u>.

Explanation:

Method is a small piece of program that is used to solve the particular problem. The problem may be repeat at multiple instances, so a method is written and call it on multiple places where it needed.

There are two different types of parameters used in methods. Actual parameters and formal parameters. Actual parameters are those, that are used in method call contain actual values that need to processed through method. Formal parameters are used for the purpose of declaration and accept the values that contains by actual parameters at the time of method call.

You might be interested in
Which of the following statements are true of
Gennadij [26K]

Answer:

Option A - They are responsible for writing programming

Option B - They are usually strong problem-solvers

Explanation:

A software engineer needs to be a strong problem solver and he/she must be able to write program/code. He/She is not required to conduct experiments in labs and also it is not essential for them to hold masters degree as even the non computer science or IT background people are working as software engineer.

Hence, both option A and B are correct

8 0
3 years ago
A key step in the ____ approach to incident response is to discover the identify of the intruder while documenting his or her ac
muminat

Answer:d)apprehend and prosecute

Explanation: A intruder is a person who tries to access the system or damage it in an unauthorized manner. The person who is found with any intruding activity should be discovered.

Apprehending means of getting aware and prosecute defines the accusing of any person committing a crime .These activities define the nature of the intruder whose trying to commit the crime and should be detected while he  is pursuing the activity.Thus , the correct option is option(d).

7 0
3 years ago
Translate the following MIPS code to C. Assume that the variables f, g, h, i, and j are assigned to registers $s0, $s1, $s2, $s3
Romashka [77]

Answer:

f = 2 * (&A[0])

See explaination for the details.

Explanation:

The registers $s0, $s1, $s2, $s3, and $s4 have values of the variables f, g, h, i, and j respectively. The register $s6 stores the base address of the array A and the register $s7 stores the base address of the array B. The given MIPS code can be converted into the C code as follows:

The first instruction addi $t0, $s6, 4 adding 4 to the base address of the array A and stores it into the register $t0.

Explanation:

If 4 is added to the base address of the array A, then it becomes the address of the second element of the array A i.e., &A[1] and address of A[1] is stored into the register $t0.

C statement:

$t0 = $s6 + 4

$t0 = &A[1]

The second instruction add $t1, $s6, $0 adding the value of the register $0 i.e., 32 0’s to the base address of the array A and stores the result into the register $t1.

Explanation:

Adding 32 0’s into the base address of the array A does not change the base address. The base address of the array i.e., &A[0] is stored into the register $t1.

C statement:

$t1 = $s6 + $0

$t1 = $s6

$t1 = &A[0]

The third instruction sw $t1, 0($t0) stores the value of the register $t1 into the memory address (0 + $t0).

Explanation:

The register $t0 has the address of the second element of the array A (A[1]) and adding 0 to this address will make it to point to the second element of the array i.e., A[1].

C statement:

($t0 + 0) = A[1]

A[1] = $t1

A[1] = &A[0]

The fourth instruction lw $t0, 0($t0) load the value at the address ($t0 + 0) into the register $t0.

Explanation:

The memory address ($t0 + 0) has the value stored at the address of the second element of the array i.e., A[1] and it is loaded into the register $t0.

C statement:

$t0 = ($t0 + 0)

$t0 = A[1]

$t0 = &A[0]

The fifth instruction add $s0, $t1, $t0 adds the value of the registers $t1 and $t0 and stores the result into the register $s0.

Explanation:

The register $s0 has the value of the variable f. The addition of the values stored in the regsters $t0 and $t1 will be assigned to the variable f.

C statement:

$s0 = $t1 + $t0

$s0 = &A[0] + &A[0]

f = 2 * (&A[0])

The final C code corresponding to the MIPS code will be f = 2 * (&A[0]) or f = 2 * A where A is the base address of the array.

3 0
3 years ago
This assignment is to code a simple hangman game. The game should choose a random word out of a list of words that are coded int
pshichka [43]

Answer:

Programming language not stated.

I'll use python for this question

Explanation:

import random

# library that we use in order to choose

# on random words from a list of words

words = ['rain, 'computer', 'science', 'program, 'python', 'mathematics', 'player', 'condition','reverse', 'water', 'board', 'geeks','learn','school','days','scholar','collar','flood','house','flies']

# Function will choose one random word from this list of words

word = random.choice(words)

print("Guess the word")

guesses = ''"

# 5 turns

turns = 5

while turns > 0:

# counts the number of times a user fails

failed = 0

# all characters from the input word taking one at a time.

for char in word:

# comparing that character with the character in guesses

if char in guesses:

print(char)

else:

print("_")

# for every failure 1 will be incremented in failure

failed += 1

if failed == 0:

# user will win the game if failure is 0 and 'You Win' will be given as output

print("You Win")

# this print the correct word

print("The word is: ", word)

break

# if user has input the wrong alphabet then it will ask user to enter another alphabet

guess = input("guess a character:")

# every input character will be stored in guesses

guesses += guess

# check input with the character in word

if guess not in word:

turns -= 1

# if the character doesn’t match the word then “Wrong” will be given as output

print("Wrong")

# this will print the number of turns left for the user

print("You have", + turns, 'more guesses')

if turns == 0:

print("You Loose")

7 0
3 years ago
Which one of the following statements most fully describes the general capabilities of desktop publishing software?
OleMash [197]
The answer is B.
<span> desktop publishing program must be able to take text and graphics from a number of sources and allow these elements to be arranged on a page. 
The main purpose of a destkop publishing program is to aid user in creating documents using its page layout so it could generate printable media with higher quality compared to the one that is handmade.</span>
7 0
4 years ago
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