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Rus_ich [418]
3 years ago
8

Sam wanted to buy candy for all of his friends to share at lunch. one pound of chocolate cost 6.95 , but Sam only needs 0.6 of a

pound. what will be the total cost for the chocolates Sam buys?​
Mathematics
2 answers:
frosja888 [35]3 years ago
7 0

Answer:

4.17 is how much she will pay.

Gennadij [26K]3 years ago
7 0
The answer is 4.17 because one entire pound of chocolate is 6.95*1.0 but if you multiply 6.95*0.6 of a pound it is equal to 4.17
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yawa3891 [41]

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5 0
3 years ago
Assume the total cost of a college education will be $235,000 when your child enters college in 18 years. You presently have $53
Andrei [34K]

Answer:

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1+r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

A = $235,000

P = $53,000

n = 1 because it was compounded once in a year.

t = 18 years

Therefore,.

235000 = 53000(1 + r/1)^1 × 18

235000/53000 = (1 + r)^18

4.43 = (1 + r)^18

Raising both sides to the power of 1/18, it becomes

4.43^(1/18) = (1 + r)^18 × 1/18

1.086 = 1 + r

r = 1.086 - 1

r = 0.086

r = 0.086 × 100 = 8.6%

6 0
3 years ago
The Wright brothers made the world’s first flight in a power-driven airplane.
Andru [333]
30 because 1 is the 10 feet so the 3 must be 30 once you multiply it by 10
6 0
3 years ago
Which is greater than, less than, or equal?
laila [671]

Answer:


Step-by-step explanation:

a whole number such as 6  can be rewritten as 6/1



6 0
3 years ago
Read 2 more answers
What the answer fast
DanielleElmas [232]

Answer:

HI = 13

Step-by-step explanation:

The triangle that is shown is a 45-45-90 triangle, so we know that GH = GJ = 9 and IJ = 13, we are able to solve for HI.

Technically, IJ = HI, since both triangles are congruent. Both IJ and HI will be 13.

5 0
3 years ago
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