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Xelga [282]
3 years ago
8

Answer BOTH questions and show your work (either type out your steps, use the writing tool or upload a picture of your work):

Mathematics
1 answer:
Viktor [21]3 years ago
3 0

9514 1404 393

Answer:

  A: x = 2

  B: x < 5

Step-by-step explanation:

<u>Part A</u>:

Substitute the given value and solve for x.

  f(x) = 3(x +6)

  24 = 3(x +6)

  8 = x +6 . . . . . . divide by 3

  2 = x . . . . . . . . . subtract 6

__

<u>Part B</u>:

Eliminate parentheses, solve the 3-step inequality.

  2(x -4) > 4x -18

  2x -8 > 4x -18

  -8 > 2x -18 . . . . . . . subtract 2x

  10 > 2x . . . . . . . . . . add 18

   5 > x . . . . . . . . . . . divide by 2

The solutions for x include any value less than 5.

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Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level. how m
GalinKa [24]

The addison see to the horizon at 2 root 2mi.

We have given that,Kaylib’s eye-level height is 48 ft above sea level, and addison’s eye-level height is 85 and one-third ft above sea level.

We have to find the how much farther can addison see to the horizon

<h3>Which equation we get from the given condition?</h3>

d=\sqrt{\frac{3h}{2} }

Where, we have

d- the distance they can see in thousands

h- their eye-level height in feet

For Kaylib

d=\sqrt{\frac{3\times 48}{2} }\\\\d=\sqrt{{3(24)} }\\\\\\d=\sqrt{72}\\\\d=\sqrt{36\times 2}\\\\\\d=6\sqrt{2}....(1)

For Addison h=85(1/3)

d=\sqrt{\frac{3\times 85\frac{1}{3} }{2} }\\d\sqrt{\frac{256}{2} } \\d=\sqrt{128} \\d=8\sqrt{2} .....(2)

Subtracting both distances we get

8\sqrt{2}-6\sqrt{2}  =2\sqrt{2}

Therefore, the addison see to the horizon at 2 root 2mi.

To learn more about the eye level visit:

brainly.com/question/1392973

5 0
3 years ago
Please please help me please
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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago
NEvermind ..............
Vadim26 [7]
If you still need an answer but it’s B
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