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3 years ago

How can you use 4s facts to find 7x8

Mathematics

2 answers:

quester [9]3 years ago

7 0

WHAT'S 4s? Is that a type of math

Rus_ich [418]3 years ago

6 0

Because 7 x 8 = 56 56 divided by 4= 14

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Lisa says that 43 is a 2 digit odd number that is a composit is she correct

Kamila [148]

No!

43 doesn't divide by anything.

6 0

3 years ago

Can someone help me ? i have no clue how to figure this out

Ad libitum [116K]

$\cos t (\sec t - \cos t) = \sin^2 t$

$\cos t (\dfrac{1}{\cos t} - \cos t) = \sin^2 t$

$\dfrac{\cos t}{\cos t} - \cos^2 t = \sin^2 t$

$1 - \cos^2 t = \sin^2 t$

Use the identity: $\sin^2 t + \cos^2 t = 1$ and solve for $\sin^2 t$ . You get: $\sin^2 t = 1 - \cos^2 t$

Do the substitution on the left side to get:

$\sin^2 t = \sin ^2 t$

5 0

3 years ago

Read 2 more answers

How many nonzero terms of the Maclaurin series for ln(1 x) do you need to use to estimate ln(1.4) to within 0.001?

Vilka [71]

Answer:

The estimate of In(1.4) is the first five non-zero terms.

Step-by-step explanation:

From the given information:

We are to find the estimate of In(1 . 4) within 0.001 by applying the function of the Maclaurin series for f(x) = In (1 + x)

So, by the application of Maclurin Series which can be expressed as:

$f(x) = f(0) + \dfrac{xf'(0)}{1!}+ \dfrac{x^2 f"(0)}{2!}+ \dfrac{x^3f'(0)}{3!}+... \ \ \ \ \ --- (1)$

Let examine f(x) = In(1+x), then find its derivatives;

f(x) = In(1+x)

$f'(x) = \dfrac{1}{1+x}$

f'(0) $= \dfrac{1}{1+0}=1$

f ' ' (x) $= \dfrac{1}{(1+x)^2}$

f ' ' (x) $= \dfrac{1}{(1+0)^2}=-1$

f ' ' '(x) $= \dfrac{2}{(1+x)^3}$

f ' ' '(x) $= \dfrac{2}{(1+0)^3} = 2$

f ' ' ' '(x) $= \dfrac{6}{(1+x)^4}$

f ' ' ' '(x) $= \dfrac{6}{(1+0)^4}=-6$

f ' ' ' ' ' (x) $= \dfrac{24}{(1+x)^5} = 24$

f ' ' ' ' ' (x) $= \dfrac{24}{(1+0)^5} = 24$

Now, the next process is to substitute the above values back into equation (1)

$f(x) = f(0) + \dfrac{xf'(0)}{1!}+ \dfrac{x^2f' \ '(0)}{2!}+\dfrac{x^3f \ '\ '\ '(0)}{3!}+\dfrac{x^4f '\ '\ ' \ ' \(0)}{4!}+\dfrac{x^5f' \ ' \ ' \ ' \ '0)}{5!}+ ...$

$In(1+x) = o + \dfrac{x(1)}{1!}+ \dfrac{x^2(-1)}{2!}+ \dfrac{x^3(2)}{3!}+ \dfrac{x^4(-6)}{4!}+ \dfrac{x^5(24)}{5!}+ ...$

$In (1+x) = x - \dfrac{x^2}{2}+\dfrac{x^3}{3}-\dfrac{x^4}{4}+\dfrac{x^5}{5}- \dfrac{x^6}{6}+...$

To estimate the value of In(1.4), let's replace x with 0.4

$In (1+x) = x - \dfrac{x^2}{2}+\dfrac{x^3}{3}-\dfrac{x^4}{4}+\dfrac{x^5}{5}- \dfrac{x^6}{6}+...$

$In (1+0.4) = 0.4 - \dfrac{0.4^2}{2}+\dfrac{0.4^3}{3}-\dfrac{0.4^4}{4}+\dfrac{0.4^5}{5}- \dfrac{0.4^6}{6}+...$

Therefore, from the above calculations, we will realize that the value of $\dfrac{0.4^5}{5}= 0.002048$ as well as $\dfrac{0.4^6}{6}= 0.00068267$ which are less than 0.001

Hence, the estimate of In(1.4) to the term is $\dfrac{0.4^5}{5}$ is said to be enough to justify our claim.

∴

The estimate of In(1.4) is the first five non-zero terms.

8 0

3 years ago

Three highways connect the centers of three towns and

Vera_Pavlovna [14]

we know that

The circumcenter of a triangle is the point where the perpendicular bisectors of the sides intersect. It is also the center of the circumcircle, the circle that passes through all three vertices of the triangle

The distance of the circumcenter to the vertices of the triangle is equal to the radius of the circle

see the attached figure to better understand the problem

therefore

the answer is

The cell phone company must be place the new cell tower in the circumcenter of the triangle formed by the center of the three towns

4 0

3 years ago

41-24/(4+8)-[36+{12x(10/2)}+4]

amid [387]

Answer:

-61

Step-by-step explanation:

simply put parentheses in your priority

means

1) ()

2) ^√

3) ÷×

4) +-

4 0

3 years ago