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Bad White [126]
3 years ago
11

Excluding any outliers, what is the mean of the data set {21, 14, 11, 26, 33, 61, 29}?

Mathematics
2 answers:
Mumz [18]3 years ago
5 0

Answer: The mean is 22.

Step-by-step explanation:

If you reorder the terms, (11, 14, 21, 26, 29, 33, 61) you can see that 61 is an outlier. Exclude the value.

Now, add the leftover values together (11, 14, 21, 26, 29, 33) which equals 134.

Finally divide 134/6 (Amount of values) and this equals 22.3(repeating).

Round down to 22.

Hope this helps!

sashaice [31]3 years ago
3 0

Answer: 22

Step-by-step explanation:

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3 0
2 years ago
the average starting salary for this year's graduates at a large university (lu) is $55,000 with a standard deviation of $6,000.
alexira [117]

0.84% of the graduates will receive the tax break

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean  and standard deviation , the z-score of a measure X is given by:

Z = x - μ / σ

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This is the pvalue of Z when X = $39,600. So

z = 39600 - 55000 / 6000

z = -2.5

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0.84% of the graduates will receive the tax break.

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7 0
1 year ago
Using suitable identity find 231^222-131^2​
Sliva [168]

Given:

Consider the expression is

231^2-131^2

To find:

The value of given expression using a suitable identity.

Solution:

We have,

231^2-131^2

Using the identity a^2-b^2=(a-b)(a+b), we get

231^2-131^2=(231-131)(231+131)

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231^2-131^2=36200

Therefore, the value of the given expression is 231^2-131^2=36200.

7 0
2 years ago
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