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3 years ago

PLEASE HELPPPP!!!!!!!

Mathematics

2 answers:

jek_recluse [69]3 years ago

8 0

Answer:

the length between them is 4

Step-by-step explanation:

from Q - T

both are at -9 so its a straight line.

the difference between -2 and 2 is 4

-2 , -1, 0, 1, 2,

Temka [501]3 years ago

6 0

Answer:

Step-by-step explanation:

Q and T are on the same line.

-9 is the x value for both points.

All you are left with is the distance between -2 and 2.

Subtract and take absolute value if you come up with a negative answer.

2 - -2 = 4

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Step-by-step explanation:

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3 years ago

Construct the confidence interval for the population standard deviation for the given values. Round your answers to one decimal

Alex777 [14]

Answer:

The correct answer is " $2.633< \sigma < 4.480$ ".

Step-by-step explanation:

Given:

n = 21

s = 3.3

c = 0.9

now,

$df = n-1$

$=20$

⇒ $x^2_{\frac{\alpha}{2}, n-1 }$ = $x^2_{\frac{0.9}{2}, 21-1 }$

= $31.410$

⇒ $x^2_{1-\frac{\alpha}{2}, n-1 }$ = $10.851$

hence,

The 90% Confidence interval will be:

= $\sqrt{\frac{(n-1)s^2}{x^2_{\frac{\alpha}{2}, n-1 }} } < \sigma < \sqrt{\frac{(n-1)s^2}{x^2_{1-\frac{\alpha}{2}, n-1 }}$

= $\sqrt{\frac{(21-1)3.3^2}{31.410} } < \sigma < \sqrt{\frac{(21.1)3.3^2}{10.851} }$

= $\sqrt{\frac{20\times 3.3^2}{31.410} } < \sigma < \sqrt{\frac{20\times 3.3^2}{10.851} }$

= $2.633< \sigma < 4.480$

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3 years ago

What is 0.68 expressed as a fraction in simplest form? Both the 6 and the 8 repeat.

andreev551 [17]

Answer:

68/99

Step-by-step explanation:

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Let x= .68686868668repeating

Multiply by 100

100x = 68.686868686repeating

Subtract x = .68686868repeating from this equation

100x = 68.686868686repeating

-x = .68686868repeating

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3 years ago

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3 years ago

Day care centers expose children to a wider variety of germs than the children would be exposed to if they stayed at home more o

Ostrovityanka [42]

Answer:

a) The study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is approximately 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is approximately 0.8565

c) The odds ratio is approximately 0.6780

d) The 95% CI is approximately 0.523 < OR < 0.833

e) i) Yes

ii) Children with more social activity have a higher occurrence of acute lymphoblastic leukemia

Step-by-step explanation:

a) An experimental study is a study in which the researcher adds inputs to the study and then monitors the outcomes

An observational study is one in which the researcher observes risk factors and does not intervene in the process

Therefore, the study is an observational study

b) The proportion of children with significant social activity in children with acute lymphoblastic leukemia is $\hat p_1$ = 1020/1272 = 85/106 = $0.8\overline {0188679245283}$ ≈ 0.802

The proportion of children with significant social activity in children without acute lymphoblastic leukemia is $\hat p_2$ = 5343/6238 ≈ 0.8565

c) We have the following two way table;

$\begin{array}{ccc}Lymphoblastic \ Leukemia &With \ Social \ Activity & Without \ Social \ Activity\\With&1020 \ (a)&252 \ (b)\\Without&5343 \ (c)&895 \ (d) \end{array}$

$The \ odds \ ratio = \dfrac{1,020 \times 895}{5,343 \times 252} \approx 0.6780$

The odds ratio ≈ 0.6780

d) The 95% confidence interval for the odds ratio is given as follows;

$95 \% \ CI = OR \ \pm \ 1.96 \times \sqrt{\dfrac{1}{a} +\dfrac{1}{b}+\dfrac{1}{c}+\dfrac{1}{d}}$

Where;

a = 1020, b = 252, c = 5343, d = 895

Therefore;

$95 \% \ CI \approx 0.6780 \ \pm \ 1.96 \times \sqrt{\dfrac{1}{1,020} +\dfrac{1}{252}+\dfrac{1}{5,343}+\dfrac{1}{895}} \approx 0.678 \pm0.155$

The 95% CI ≈ 0.523 < OR < 0.833

e) i) Given that the observed Odds Ratio is within the Confidence Interval, therefore, there is an indication that the amount of social activity is associated with acute lymphoblastic leukemia

ii) Based on the proportion of the study findings, children with more social activity have a higher occurrence of acute lymphoblastic leukemia

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3 years ago