Answer: However, in real life it depends on the shape of the actual presents. If two sheets are used for the 2 presents. There should be enough left from those sheets to use for the third present. (They should be taped together.)
Step-by-step explanation: 6/3 then 3 over 8 ––> 3/8
6/ 27/8
= 6/1 / divide 27/8
= 6^2 /1 x 8/27 ^9 (^) –––> this mean square root of 2 or 9
6 cancels and 27 cancel
= 16/9
=1 7/9
However you will still need to buy 2 sheets
Slope is defined as the rate of change, in this case the change in y with respect to x. In standard form for a binomial linear equation, y = mx + b. The constants m and b are the slope and intercept, respectively. For your equation, the slope is -2 and the intercept is 0. The domain (possible values of x) for this graph is (-∞, ∞) and the range (possible values of y) is also (-∞, ∞).
A circle can’t weigh any inches just gonna say that now. Assuming you meant “height” of 3.125 inches, then the circumference is C=2(pi)r, where r is 1/2 the height (radius is half of the diameter, this situation the diameter being 3.125 inches.
Circumference would be approximately 9.8174770424681 inches—
Or shortened to 2 decimals it’s approximately
9.82 inches
Or approximately
9.8 inches
Or approximately
10 inches
Answer:
<h2><em>
Three to the three fifths power.</em></h2>
Step-by-step explanation:
The given expression is
![\sqrt{3\sqrt[5]{3} }](https://tex.z-dn.net/?f=%5Csqrt%7B3%5Csqrt%5B5%5D%7B3%7D%20%7D)
To simplify this expression, we have to use a specific power property which allow us to transform a root into a power with a fractional exponent, the property states:
![\sqrt[n]{x^{m}}=x^{\frac{m}{n}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5E%7Bm%7D%7D%3Dx%5E%7B%5Cfrac%7Bm%7D%7Bn%7D%7D)
Applying the property, we have:
![\sqrt{3\sqrt[5]{3}}=\sqrt{3(3)^{\frac{1}{5}}}=(3(3)^{\frac{1}{5}})^{\frac{1}{2}}](https://tex.z-dn.net/?f=%5Csqrt%7B3%5Csqrt%5B5%5D%7B3%7D%7D%3D%5Csqrt%7B3%283%29%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%7D%3D%283%283%29%5E%7B%5Cfrac%7B1%7D%7B5%7D%7D%29%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D)
Now, we multiply exponents:
Then, we sum exponents to get the simplest form:
![3^{\frac{1}{2}}3^{\frac{1}{10}}=3^{\frac{1}{2}+\frac{1}{10}} =3^{\frac{10+2}{20}}=3^{\frac{12}{20}} \\\therefore \sqrt{3\sqrt[5]{3}}=3^{\frac{3}{5} }](https://tex.z-dn.net/?f=3%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D3%5E%7B%5Cfrac%7B1%7D%7B10%7D%7D%3D3%5E%7B%5Cfrac%7B1%7D%7B2%7D%2B%5Cfrac%7B1%7D%7B10%7D%7D%20%3D3%5E%7B%5Cfrac%7B10%2B2%7D%7B20%7D%7D%3D3%5E%7B%5Cfrac%7B12%7D%7B20%7D%7D%20%20%5C%5C%5Ctherefore%20%5Csqrt%7B3%5Csqrt%5B5%5D%7B3%7D%7D%3D3%5E%7B%5Cfrac%7B3%7D%7B5%7D%20%7D)
Therefore, the right answer is <em>three to the three fifths power.</em>
