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hammer [34]
3 years ago
7

If the discriminant is positive then the solution will be:

Mathematics
2 answers:
Marrrta [24]3 years ago
5 0
If the discriminant, b^2 — 4ac is positive (or > 0), then the solution will be two (2) distinct real solutions.

If the discriminant is positive ( > 0), there are 2 real solutions.
If the discriminant is = 0, there is 1 real repeated solution.
If the discriminant is negative (< 0), there are 2 complex solutions (but no real solutions).
Sindrei [870]3 years ago
3 0

Answer:

Solutions have 2 real roots.

Step-by-step explanation:

Discriminant determines the solutions of quadratic equation.

If the value of discriminant is greater than 0 or D > 0 or D is positive then there are 2 real roots.

If the value of discriminant is 0, there is one real root.

If the value of discriminant is less than 0 or in negative then there are no real roots.

<u>F</u><u>o</u><u>r</u><u>m</u><u>u</u><u>l</u><u>a</u>

Discriminant can be found using:

\displaystyle \large{D =  {b}^{2}  - 4ac}

The discriminant derives from Quadratic Formula.

\displaystyle \large{x =  \frac{ - b \pm  \sqrt{ {b}^{2} - 4ac } }{2a} }

Now you should know why D > 0 gives 2 real roots because of ± which determines 2 solutions.

D = 0 gives one real root because x would be -b/2a

D < 0 gives no real roots because in square root, the value is negative which does not exist in real number.

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ioda
8x+8c+164-6
=8x+8c+158
7 0
3 years ago
Read 2 more answers
Choose ALL possible answers
muminat
Select all the correct answers:
1) Yes

2) No
x=8→h(8)=2(8)^2+5(8)+2=2(64)+40+2=128+40+2→h(8)=170
x=8→f(8)=3^8+2=6,561+2→f(8)=5,563>170=h(8)

3) Yes

4) No

5) Yes
rg=[g(3)-g(2)]/(3-2)=[g(3)-g(2)]/1→rg=g(3)-g(2)
g(3)=20(3)+4=60+4→g(3)=64
g(2)=20(2)+4=40+4→g(2)=44
rg=64-44→rg=20

rf=f(3)-f(2)
f(3)=3^3+2=27+2→f(3)=29
f(2)=3^2+2=9+2→f(2)=11
rf=29-11→rf=18

rh=h(3)-h(2)
h(3)=2(3)^2+5(3)+2=2(9)+15+2=18+15+2→h(3)=35
h(2)=2(2)^2+5(2)+2=2(4)+10+2=8+10+2→h(2)=20
rh=35-20→rh=15

rg=20>18=rf
rg=20>15=rh

6)  No
x=4→g(4)=20(4)+4=80+4→g(4)=84
x=4→h(4)=2(4)^2+5(4)+2=2(16)+20+2=32+20+2→h(4)=54
x=4→f(4)=3^4+2=81+2→f(4)=83>54=h(4)
f(4)=83<84=g(4)
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3 years ago
Which area model can u use to fine * find 39 x73
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3 0
3 years ago
During a spring clearance sale, Sears advertise 1/4 off the list of Model II microwave ovens and an additional 1/5 off the sale
ozzi

Answer:

$ 75.

Step-by-step explanation:

From the information above,

List price of model II = $240

Sale price of the clearance sale is 1/4 off the list price of Model II microwave oven and additional 1/5 of the sale price for oven that are scratched and dented.

Therefore,

Let the sale price be X,

= (1/4)*(list price) + (1/5)*X

X = (1/4)*(240) + (1/5)*X

X = 60 + (1/5)X

Solving for X,

X - (1/5)X = 60

(4/5)X = 60

X = (60*5)/4

= $75.

4 0
3 years ago
The cost C of moving rubble is proportional to the product of the mass M of the rubble and the distance D the rubble must be mov
Mandarinka [93]

Answer:

a) C(M,D) = KMD

b) $12,000                  

Step-by-step explanation:

We are given the following information in the question:

The cost C of moving rubble is proportional to the product of the mass M of the rubble and the distance D the rubble must be moved.

This can be written as:

a)

C \propto M\times D\\C = KMD,\\\text{where K is the constant of proportionality.}

C(M,D) = KMD

b) It costs 50 dollars to move 1 ton of rubble 1 mile

50 = K\times 1\times 1\\\Rightarrow K= 50

We have to find  cost to move 16 tons 15 miles.

Putting the values in the function:

C(16,15) = 50\times 16\times 15 = 12000

Thus, $12,00 is the cost to move 16 tons 15 miles.

3 0
3 years ago
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