Answer:
2+w+p
Step-by-step explanation:
Answer:
- y = 81-x
- the domain of P(x) is [0, 81]
- P is maximized at (x, y) = (54, 27)
Step-by-step explanation:
<u>Given</u>
- x plus y equals 81
- x and y are non-negative
<u>Find</u>
- P equals x squared y is maximized
<u>Solution</u>
a. Solve x plus y equals 81 for y.
y equals 81 minus x
__
b. Substitute the result from part a into the equation P equals x squared y for the variable that is to be maximized.
P equals x squared left parenthesis 81 minus x right parenthesis
__
c. Find the domain of the function P found in part b.
left bracket 0 comma 81 right bracket
__
d. Find dP/dx. Solve the equation dP/dx = 0.
P = 81x² -x³
dP/dx = 162x -3x² = 3x(54 -x) = 0
The zero product rule tells us the solutions to this equation are x=0 and x=54, the values of x that make the factors be zero. x=0 is an extraneous solution for this problem so ...
P is maximized at (x, y) = (54, 27).
Answer:
1 / 9
Step-by-step explanation:
Given the number cube :
(11,12,11,12,20,20)
Spinner : (G, H, J)
Probability = required outcome / Total possible outcomes
P(20) = 2 / 6 = 1/3
P(H) = 1 / 3
P(20 and H) = P(20) * P(H) = 1/3 * 1/3 = 1 /9
Answer:
Product (multiplication) of 2a+3b-c and 2a+3b-c is −2ac+2a+6b−c.
Explanation:
2a+3b−c(2)a+3b−c
= 2a+3b+−2ac+3b+−c
Combine Like Terms:
= 2a+3b+−2ac+3b+−c
= (−2ac)+(2a)+(3b+3b)+(−c)
= −2ac+2a+6b+−c
