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Dennis_Churaev [7]
3 years ago
10

Is 8/6 greater than 4/3

Mathematics
1 answer:
Deffense [45]3 years ago
4 0

Answer:

no, they are equal

Step-by-step explanation:

8/6=1.3

4/3=1.3

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Find the vertices and locate the foci for the hyperbola whose equation is given. 49x2 - 100y2 = 4900
Fiesta28 [93]
<h2>Answer:</h2>

A hyperbola is the set of all points in a plane such that  the difference of whose  distances from two distinct fixed points called foci is a positive constant. In this problem, we have the following equation:

49x^2-100y^2=4900

What if we divide the whole equation by 49 \times 100=4900? Well the result is:

\frac{1}{4900}(49x^2-100y^2=4900) \\ \\ \frac{49x^2}{4900}-\frac{100y^2}{4900}=\frac{4900}{4900} \\ \\ \frac{x^2}{100}-\frac{y^2}{49}=1 \\ \\ \boxed{\frac{x^2}{10^2}-\frac{y^2}{7^2}=1}

The standard form of the equation of the hyperbola given that the vertex lies on the origin is:

\frac{x^2}{a^2}-\frac{y^2}{b^2}=1

SO THE VERTICES ARE:

\boxed{(a,0)=(10,0) \ and \ (-a,0)=(-10,0)}

Calculating the foci:

We \ know \ that \ foci \ are: \\ \\ (-c,0) \ and \ (c.0) \\ \\ Also: \\ \\ c=\sqrt{a^2+b^2} \\ \\ c=\sqrt{100+49} \therefore c=\sqrt{149}

SO THE FOCI ARE:

\boxed{(-\sqrt{149},0) \ and \ (\sqrt{149},0)}

5 0
3 years ago
A team of five kids is randomly chosen from a class of 20 students. An outcome of the selection process is the set of five kids
vichka [17]

Answer:

S= 4

Step-by-step explanation:

Given

Total = 20

Selection = 5

Required

Determine the size of sample space

Represent this with S

S is calculated by dividing the total number of kids by the number of selection.

S = \frac{Total}{Selection}

S = \frac{20}{5}

S= 4

<em>Hence, the sample space has a size of 4</em>

7 0
3 years ago
al made a treehouse last summer. He started by making a model. the model included a window with height 1/3 inch. and width 1/6 i
IrinaK [193]

Answer:

27

Step-by-step explanation:

4 0
3 years ago
Convert (CAB) 16 to decimal<br><br>need help asap
Mrrafil [7]

Remark

So CAB is a base 16 number? I hope that's correct. I'll treat it that way. If I am incorrect, please leave a note and I'll modify my answer accordingly.

Expand

A = 10 in decimal

B = 11  in decimal

C = 12 in decimal

B is the "units" value in decimal it is 11

A is the "tens" value or 12 place and in decimal you would get 12 * 10 = 120

C is the "hundreds" value or 12^2 place and in decimal you would get 144*12 =1728

Now you need to all all three results together. 11 + 120 + 1728 = 1850

Answer

(CAB)_16 = 1850 in decimal

6 0
3 years ago
Read 2 more answers
oki i need help with this problems! it doesn't matter if you do it for me or help me (please help I need this due tomorrow and i
stich3 [128]

Answer:

Here:

Step-by-step explanation:

You choose 2,4,6,8,10 as your solution points, or in other words the numbers you with substitute in for x.

The equation is:

y= 1/2x+1

So what we would do is take one number from the list above (2,4,6,8.10) and put it in for are.

So, Thats how you do it, I attached a completed version of your paper below!

7 0
3 years ago
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