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saveliy_v [14]
3 years ago
12

the remains of an ancient ball court include a rectangular playing alley with a perimeter of about 48 M. the length of the alley

is 5 times the width. find the length and the width of the playing alley​
Mathematics
1 answer:
Firdavs [7]3 years ago
8 0

Answer:

Length is 20 m and width is 4 m.

Step-by-step explanation:

Given:

Perimeter of the rectangular alley, P=48\textrm{ m}

Length is 5 times the width.

Let width be x.

So, as per question,

Length,l = 5x

Now, perimeter of rectangle is given as:

P=2(l+b)

Plug in 48 for P, 5x for l and x for b.

48=2(5x+x)\\48=2(6x)\\48=12x\\x=\frac{48}{12}=4

Therefore, width is 4 m.

Length is 5x=5\times 4=20 m.

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