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3 years ago

I need to know Simplify 2a + 8(b + a) is

1 answer:

4 0

HELLO !

Okay so what you do is eliminate the parenthesis in the equation because it really helps

So you would multiply 8 and b
Also multiple 8 and a

You would get 8b and 8a

Your equation would look like ...

2a + 8b + 8a = ...

Now you add the alike things in the equation 

8a and 2a are the alike things.

Now you would have ...

10a + 8b = ?

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2x-y=4 and y=-2x+8 what is the value of x

LenKa [72]

Answer:

x=3

y=2

(3,2)

Step-by-step explanation:

7 0

3 years ago

Evaluate expression if a = 2. a² - 5a - 6

Blababa [14]

Answer:

-12.

Step-by-step explanation:

a^2 - 5a - 6

When a = 2 we have

2^2 - 5(2) - 6

= 4 - 10 - 6

= -12.

7 0

3 years ago

Read 2 more answers

I need the correct answer for questions 1

katovenus [111]

The truth values of the propositions are false, true and false

<h3>How to determine the true values?</h3>

The Boolean variables are given as:

p = false

r = false

q = true

s = true

The truth values of the propositions are as follows:

1. (s → (p ∧ ¬ r)) ∧ ((p → (r ∨ q)) ∧ s)

As a general rule:

∧ means and

¬ not

∨ or

So, we have:

(true → (false ∧ ¬ false)) ∧ ((false → (false ∨ true)) ∧ true)

¬ false= true.

So, we have:

(true → (false ∧ true)) ∧ ((false → (false ∨ true)) ∧ true)

false ∧ true = false and false ∨ true = true

So, we have:

(true → false) ∧ ((false → true) ∧ true)

false → true = true and true → false = false

So, we have:

(false) ∧ (true ∧ true)

true ∧ true = true

So, we have:

false ∧ true

Lastly

false ∧ true = false

Hence, the truth value of (s → (p ∧ ¬ r)) ∧ ((p → (r ∨ q)) ∧ s) is false

2. ((p ∧ ¬ q) → (q ∧ r)) → (s ∨ ¬q)

This means

((false ∧ ¬ true) → (true ∧ false)) → (true ∨ ¬true)

Using the established rules in (1), we have:

((false ∧ false) → (true ∧ false)) → (true ∨ false)

This gives

((false → false)) → true

This gives

true → true

Lastly, we have:

true

Hence, the truth value of ((false ∧ ¬ true) → (true ∧ false)) → (true ∨ ¬true) is true

3. (p → q) ∧ (q → r)

This gives

(false → true) ∧ (true → false)

Using the established rules in (1), we have:

true ∧ false

This gives

false

Hence, the truth value of (p → q) ∧ (q → r) is false