All categories

3 years ago

Help me pleaseeee asap, thanks!

Mathematics

1 answer:

olya-2409 [2.1K]3 years ago

6 0

Answer:

see below

Step-by-step explanation:

$\sqrt{64} + \sqrt{-144} = \sqrt{8^2} + \sqrt{-1 \times 12^2}$

$~~~~~~~~ = 8 + i \times \sqrt{12^2}$

$~~~~~~~~ = 8 + 12i$

You might be interested in

What is the area of rectangle ABCD in square units ?

Licemer1 [7]

Answer:

Step-by-step explanation:

Square units = √( 4^2 + 1^2) * √( 8^2 + 2^2)

= √17 * √68

= √1156

= 34

5 0

3 years ago

Read 2 more answers

Find (f•f)(x) when f(x) = x^2-2 and g(x)= x-1

UkoKoshka [18]

Answer:

Solution

(f+g)(x)=f(x)+g(x)

+2x+1

(f−g)(x)=f(x)−g(x)

−(2x+1)

−2x−1

(fg)(x)=f(x).g(x)

(2x+1)

=2x

(

)(x)=

g(x)

f(x)

(g(x)



=0)

2x+1



=−

)

Step-by-step explanation:

ƈǟʀʀʏ օռ ʟɛǟʀռɨռɢ

6 0

2 years ago

Find the surface area of the rectangle:<br> 8 cm<br> 5 cm<br> 12 cm

Ostrovityanka [42]

12cm is the surface

8 0

2 years ago

Read 2 more answers

Keith buys 45 tickets for rides at the amusement park. Each ride requires 6 tickets to ride. If Keith already has gone on x ride

Lynna [10]

A is the correct answer if I did it right

3 0

2 years ago

The time between telephone calls to a cable television service call center follows an exponential distribution with a mean of 1.

Ulleksa [173]

Answer:

0.52763 is the probability that the time between the next two calls will be 54 seconds or less.

0.19285 is the probability that the time between the next two calls will be greater than 118.5 seconds.

Step-by-step explanation:

We are given the following information in the question:

The time between telephone calls to a cable television service call center follows an exponential distribution with a mean of 1.2 minutes.

The distribution function can be written as:

$f(x) = \lambda e^{-\lambda x}\\\text{where lambda is the parameter}\\\\\text{Mean} = \mu = \displaystyle\frac{1}{\lambda}\\\\\Rightarrow 1.2 = \frac{1}{\lambda}\\\\\lambda = 0.84 \\f(x) = 0.84 e^{0.84 x}$

The probability for exponential distribution is given as:

$P( x \leq a) = 1 - e^{\frac{-a}{\mu}}\\\\P(a \leq x \leq b) = e^{\frac{-a}{\mu} -\frac{-b}{\mu}}$

a) P( time between the next two calls will be 54 seconds or less)

$P( x \leq 0.9)\\= 1 - e^{\frac{\frac{-54}{60}}{1.2}} = 0.52763$

0.52763 is the probability that the time between the next two calls will be 54 seconds or less.

b) P(time between the next two calls will be greater than 118.5 seconds)

$p( x > \frac{118.5}{60}) = P(x > 1.975)\\\\ = 1 - P(x \leq 1.975) \\\\= 1 -1+ e^{\frac{-1.975}{1.2}}\\\\= 0.19285$

0.19285 is the probability that the time between the next two calls will be greater than 118.5 seconds.

6 0

3 years ago