-11.1666667 should be the answer
a)
has CDF


where the last equality follows from independence of
. In terms of the distribution and density functions of
, this is

Then the density is obtained by differentiating with respect to
,

b)
can be computed in the same way; it has CDF


Differentiating gives the associated PDF,

Assuming
and
, we have


and


I wouldn't worry about evaluating this integral any further unless you know about the Bessel functions.
Answer:
y = 38
Step-by-step explanation:
The sum of the 3 angles in a triangle = 180°
Consider the angles in the large outer triangle, then
x + 46 + 78 = 180
x + 124 = 180 ( subtract 124 from both sides )
x = 56
Consider the 3 angles in the smaller inner triangle, then
y + x + 86 = 180 , that is
y + 56 + 86 = 180
y + 142 = 180 ( subtract 142 from both sides )
y = 38
Answer:
what are the optionnnnnn????