2 years ago

Find two number nearest to 8888888 which are exactly divisible by 2915

Mathematics

1 answer:

Marysya12 [62]2 years ago

3 0

Step-by-step explanation:

Given problem is to find nearest number,

= 8888888/2915

quotient = 3049

remainder= 1053

Now, 2915-1053 = 1862

8888888+1862 = 8890750

8888888-1053 = 8887835

Two numbers nearest to 8888888 which are exactly divisible by 2915 is 8887835 and 8890750

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