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wolverine [178]
3 years ago
14

Select all statements that are true about the linear equation. y=−x−1

Mathematics
1 answer:
levacccp [35]3 years ago
6 0
For point (1, -2): -2 = -1 - 1 = -2. Therefore, point (1, -2) lies on the graph of the equation.

The graph of the equation is the set of points that are solutions to the equation.

A coordinate pair on the graph of the equation is a solution to the equation.

For the point (0, -1): -1 = -(0) - 1 = 0 - 1 = -1.
Therefore, The point ( 0, −1 ) lies on the graph of the equation.
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What is the value of the expression below when x=8? 10x+5
DaniilM [7]
1. Plug in 8 into x.
The equation will be 10(8)+5
2. Solve multiplication
80+5
3. The answer is 85! Hope this helped <3
8 0
4 years ago
Given 2x² = -8, x is<br> A) -2 <br> B) 2<br> C) 2i or -2i <br> B) 4i or -4i<br> NO LINKS!!!
faust18 [17]

Answer:

2x^2=-8

2x^2/2=-8/2

x^2=-4

x=2

Step-by-step explanation:

HOPE THAT THIS IS HELPFUL.

HAVE AN AWESOME DAY.

4 0
3 years ago
Someone please tell me how to solve this
rewona [7]
The answer will be 21u^6v^8
6 0
3 years ago
A bag of ice pops contains 2 flavored raspberry, 5 flavored lemon, and 3 flavored lime. Find the probability of each event.
alexira [117]

Answer:

A) 2/10 or 20%

B) 3/10 or 30%

Step-by-step explanation:

There are 10 ice pops.

10 is going to be your denominator

Your numerator is going to be whatever amount of ice pops is.

After finding your fraction, divide the numerator by the denominator.

Lastly turn your decimal into a fraction.

2/10=0.2=20%

Hope I helped you.

8 0
3 years ago
Miki has 104 nickels and 88 dimes. She wants to divide her coins into groups where each group has the same number of nickels and
pochemuha

Given :

Miki has 104 nickels and 88 dimes.

She wants to divide her coins into groups where each group has the same number of nickels and the same number of dimes.

To Find :

Largest number of groups she can have .

Solution :

In the given question we need to find the largest number of groups she can have i.e we have to find the LCM of 104 and 88 .

Now , factorizing both of them , we get :

104=1\times 2\times 2\times 2\times 13

88=1\times 2\times 2\times 2\times 11

Form above , we can say that common factors are :

HCF=2\times 2\times 2=8

Therefore , the largest number of groups she can have is 8 .

Hence , this is the required solution .

6 0
3 years ago
Read 2 more answers
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